Explain why dielectric insertion needs a boundary condition
A dielectric is an insulating material that polarizes in an electric field. Bound positive and negative charge distributions shift slightly relative to one another, producing an opposing field. A linear dielectric that fills an ideal capacitor increases its capacitance by a factor κ, the relative permittivity. The material response must be distinguished from free charge supplied to conducting plates.
Learning outcome: Capture κ=3 in both boundary modes. Reconstruct ΔU=source work+external mechanical work. Repeat κ=1 to verify that no change yields zero work. State which quantities are constrained rather than discovered.
Starting recap
Use signed charge, vector components, inverse-square ratios and energy conservation. Distinguish potential from potential energy and name the system boundary.
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Try
Initially C₀=100 pF and V₀=10 V, so Q₀=1 nC and U₀=5 nJ. For κ=3, disconnected: C=300 pF, Q=1 nC, V=10/3 V, U=5/3 nJ. Connected: Q=3 nC, V=10 V, U=15 nJ; the source supplies 20 nJ and external mechanical work is −10 nJ.
Open the experimentPredict
If the final voltage stays at 10 V after insertion, can you still assume the free plate charge stayed at 1 nC?
Experiment
Capture κ=3 in both boundary modes. Reconstruct ΔU=source work+external mechanical work. Repeat κ=1 to verify that no change yields zero work. State which quantities are constrained rather than discovered.
Distinguish fixed charge from fixed voltage
Worked teaching model · synthetic values · Initial vacuum capacitor C0=100 pF at 10 V, separation 2 mm. A linear dielectric completely fills the gap. Disconnected retains free plate charge; connected retains voltage. Quasistatic insertion, no dissipation. The energy balance includes electrical source work and external mechanical work.
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| Quantity | Value | Unit |
|---|---|---|
| Final capacitance | 300 | pF |
| Final free plate charge | 1 | nC |
| Final potential difference | 3.3333 | V |
| Final electric field | 1666.7 | V/m |
| Final stored energy | 1.6667 | nJ |
| Change in field energy | -3.3333 | nJ |
| Electrical source work | 0 | nJ |
| External mechanical work | -3.3333 | nJ |
Accessible plot coordinates
| relative permittivity | stored energy (nJ) |
|---|---|
| 1 | 5 |
| 2 | 2.5 |
| 3 | 1.6667 |
| 4 | 1.25 |
| 5 | 1 |
Disconnected: free charge stays fixed while voltage and energy fall.
Polarization produces a field opposing the original free-charge field. With fixed voltage the source adds charge, maintaining the net field instead of letting it fall. The signed ledger obeys ΔU = source work + external mechanical work. Negative mechanical work means the external agent removes energy during controlled insertion.
Disconnected: free charge stays fixed while voltage and energy fall.
Polarization produces a field opposing the original free-charge field. With fixed voltage the source adds charge, maintaining the net field instead of letting it fall. The signed ledger obeys ΔU = source work + external mechanical work. Negative mechanical work means the external agent removes energy during controlled insertion.
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Explain how polarization and fixed voltage can coexist with an unchanged net field in the gap.
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