Infer gas amount and challenge a straight-line calibration
An equation of state becomes an experimental inference only after its controlled quantities are specified. At fixed amount and volume, P=nRT/V predicts a pressure-versus-Kelvin-temperature line through the origin. A plot against degrees Celsius has a nonzero intercept because T = θ + 273.15. Absolute pressure, not gauge pressure, belongs in this equation.
Learning outcome: Capture zero offset/no loss, then +6 kPa/no loss, then zero offset/20% final particle loss. Compare slopes, extrapolated zeros and residuals. Propose a separate measurement that distinguishes the two failure mechanisms.
Starting recap
Use absolute temperature, signed energy changes, algebraic ratios and graph areas. State the system boundary and distinguish heat transfer from temperature.
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Try
A fitted slope of 0.400 kPa/K in a 2.00 L vessel gives n=(0.400×2.00)/8.314≈0.0962 mol. A constant +6 kPa offset shifts the inferred zero but leaves that ideal slope unchanged.
Open the experimentPredict
Predict which fitted quantities change when a pressure offset is added and which change when particle loss increases.
Experiment
Capture zero offset/no loss, then +6 kPa/no loss, then zero offset/20% final particle loss. Compare slopes, extrapolated zeros and residuals. Propose a separate measurement that distinguishes the two failure mechanisms.
Challenge an ideal-gas calibration
Worked teaching model · synthetic values · Original synthetic gas record at 250, 300, 350, 400 K in 2.0 L. Initial nR=0.8 J/K. Imposed fractional loss grows linearly with temperature. Fixed pressure errors [0.2,−0.1, 0.1,−0.2] kPa are bounded, not random. Fit all four points; neither a straight fit nor extrapolation certifies a real gas thermometer.
Reset keeps your prediction, captures and practice history.
Axes rescale with settings; compare numerical values, not screen angles or apparent lengths. Solid/points show the selected model relationship or observations; the dashed comparison is explained below.
| Quantity | Value | Unit |
|---|---|---|
| Fitted pressure slope | 0.398 | kPa/K |
| Fitted intercept at 0 °C | 109.36 | kPa |
| Inferred fixed amount from slope | 0.095737 | mol |
| Initial actual amount | 0.096218 | mol |
| Extrapolated zero-pressure temperature | -274.78 | °C |
| Largest fit residual | 0.15 | kPa |
Accessible plot coordinates
| temperature (°C) | absolute pressure reading (kPa) |
|---|---|
| -23.15 | 100.2 |
| 26.85 | 119.9 |
| 76.85 | 140.1 |
| 126.85 | 159.8 |
| temperature (°C) | absolute pressure reading (kPa) |
|---|---|
| -23.15 | 100.15 |
| 126.85 | 159.85 |
An additive pressure offset can move the extrapolated zero while leaving the fitted slope unchanged.
Original pressure errors are bounded by 0.20 kPa. A fit is not proof that amount and volume were constant. Compare residuals and a separate zero-pressure calibration; extrapolation far outside measured temperatures is model-dependent.
An additive pressure offset can move the extrapolated zero while leaving the fitted slope unchanged.
Original pressure errors are bounded by 0.20 kPa. A fit is not proof that amount and volume were constant. Compare residuals and a separate zero-pressure calibration; extrapolation far outside measured temperatures is model-dependent.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Explain why fitting more points cannot remove an unrecognized common sensor bias. State what must be known before interpreting slope as one fixed amount of gas.
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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