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SCIENCE · INVESTIGATE AND EXPLAIN

Build a resultant field from source components

A field describes how a small probe would interact with fixed sources at each location. Its definition is E=F/q for a sufficiently small test charge; a positive probe feels force along E and a negative probe opposite E. The field belongs to the source configuration, not to the chosen sign of the probe. Making the probe large enough to rearrange the sources breaks that test-charge approximation.

Learning outcome: Retain equal-positive and equal-opposite source cases at height 0.30 m. Reconstruct both resultants from the table. Then change the height to 0.50 m without changing charges and compare actual magnitudes rather than rescaled screen lengths.

Starting recap

Use signed charge, vector components, inverse-square ratios and energy conservation. Distinguish potential from potential energy and name the system boundary.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

For two +2 nC sources at x=±0.20 m and a point (0,0.30) m, each source is √0.13 m away. Each contributes a vertical component k(2×10⁻⁹)(0.30)/(0.13)^(3/2)≈115.08 N/C. Net Ex=0 and net Ey≈230.16 N/C.

Open the experiment

Predict

If only the right source changes from +2 to −2 nC, which net component will vanish?

Experiment

Retain equal-positive and equal-opposite source cases at height 0.30 m. Reconstruct both resultants from the table. Then change the height to 0.50 m without changing charges and compare actual magnitudes rather than rescaled screen lengths.

Add components before magnitudes

Worked teaching model · synthetic values · Left source +2 nC at (−0.20,0) m; right source selected at (+0.20,0) m. Observe (0,height). Vacuum point-charge model; source charges fixed. Arrows are component-resolved contribution vectors at one point, not particle trajectories.

Reset keeps your prediction, captures and practice history.

+Ex+EyComponent scale: 150 screen units = 230.16 N/C
Field contributions: dashed left, dotted right, thick solid resultant (N/C)
Vectorx componenty component
Left source field76.719115.08
Right source field-76.719115.08
Net field0230.16

These are vectors at one observation point, not a spatial map. A zero vector is represented by the common origin; overlapping contributions remain distinguishable in the table.

-0.10.113.774-13.774observation x coordinate (m)x field component (N/C)

Axes rescale with settings; compare numerical values, not screen angles or apparent lengths. Solid/points show the selected model relationship or observations; the dashed comparison is explained below.

Calculated evidence ledger — synthetic teaching model
QuantityValueUnit
Net x field0N/C
Net y field230.16N/C
Net field magnitude230.16N/C
Electric potential99.735V
Accessible plot coordinates
Primary plotted points
observation x coordinate (m)x field component (N/C)
-0.1-13.774
-0.09-11.154
-0.08-8.8891
-0.07-6.9612
-0.06-5.3438
-0.05-4.0041
-0.04-2.9041
-0.03-2.0011
-0.02-1.2489
-0.01-0.59875
00
0.010.59875
0.021.2489
0.032.0011
0.042.9041
0.054.0041
0.065.3438
0.076.9612
0.088.8891
0.0911.154
0.113.774

Add signed components before finding the resultant magnitude.

All three arrows share one vector scale and start at an abstract common origin; their axes are field components, not positions. The profile uses the selected height and fixed sources. The force on a small negative probe points opposite the net field. Equipotentials are perpendicular to a nonzero electric field.

Add signed components before finding the resultant magnitude.

All three arrows share one vector scale and start at an abstract common origin; their axes are field components, not positions. The profile uses the selected height and fixed sources. The force on a small negative probe points opposite the net field. Equipotentials are perpendicular to a nonzero electric field.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Establish the model and evidence

A field describes how a small probe would interact with fixed sources at each location. Its definition is E=F/q for a sufficiently small test charge; a positive probe feels force along E and a negative probe opposite E. The field belongs to the source configuration, not to the chosen sign of the probe. Making the probe large enough to rearrange the sources breaks that test-charge approximation.

At the observation point, draw one field arrow for each source. A positive source points away from itself, a negative source toward itself. Resolve each arrow into x and y components, add signed x components and signed y components separately, then find magnitude √(Ex²+Ey²). Adding individual magnitudes first discards cancellation and usually gives the wrong answer.

Two equal positive charges at symmetric locations provide an especially clear test. Above their midpoint, the horizontal components cancel while vertical components add. Reversing only the right charge changes which components cancel: vertical components cancel and horizontal components point from the positive source toward the negative source. Symmetry is evidence for a component cancellation, not a reason to set the entire field to zero.

The arrows in this activity all start at an abstract common origin so contributions can be compared with one scale. They are not field lines or a spatial map. A field line is tangent to the field direction at every location; it is not generally a charged particle’s trajectory, since the particle can have initial velocity. The profile below the arrows samples the x component along a horizontal line at the selected height.

Worked evidence

For two +2 nC sources at x=±0.20 m and a point (0,0.30) m, each source is √0.13 m away. Each contributes a vertical component k(2×10⁻⁹)(0.30)/(0.13)^(3/2)≈115.08 N/C. Net Ex=0 and net Ey≈230.16 N/C.

Predict and investigate

If only the right source changes from +2 to −2 nC, which net component will vanish?

Retain equal-positive and equal-opposite source cases at height 0.30 m. Reconstruct both resultants from the table. Then change the height to 0.50 m without changing charges and compare actual magnitudes rather than rescaled screen lengths.

Transfer to changed conditions

At another point Ex=−120 N/C and Ey=160 N/C. Find field magnitude and force components on a −2 nC probe.

Compare the worked transfer

The magnitude is 200 N/C. Multiplying each component by −2×10⁻⁹ C gives Fx=+2.4×10⁻⁷ N and Fy=−3.2×10⁻⁷ N. Its force magnitude is 4.0×10⁻⁷ N, opposite the field direction.

Explain the boundary

Explain why a negative test charge reverses its force but does not reverse the source field.

Construct a spatial field map from separate observations

Contribution arrows at one origin are not yet a spatial map. To make one, attach each resultant arrow to the location where the field is evaluated, use one length scale, and join smooth field lines only so that their local tangents follow those arrows. In a consistently drawn field-line diagram, closer line spacing represents stronger field; lines are not material threads and their arbitrary count is not a new physical unit.

Predict, sketch and check: use a single positive point source at the origin and stipulate field magnitude 100 N/C at radius r. At (r,0), (0,r) and (−r,0), draw equal arrows pointing respectively right, up and left. At (2r,0), draw a rightward arrow one quarter as long, representing 25 N/C. Reverse the source sign and reverse every arrow without changing lengths. A point source is justified only when its physical size is negligible for these observation distances; it is not a claim that an extended object has no geometry. (Current clauses 10.1.A.1.iv and 10.3.A.3.)

Sources and authorship

Physical relationship reference. Current AP Physics 2 framework, checked 30 October 2026. These cases, diagrams and numerical records are original. All experiments are bounded browser calculations or synthetic data, not measured laboratory evidence. Do not construct or handle charged capacitors, high-voltage sources or particle-beam equipment for these activities.

Clause-level source/action reconciliation checked 31 October 2026 against the linked current framework and Fall 2026 clarification. Added packets are original virtual comparisons; no new practical or learner-completion claim.

Apply

Two equal positive sources lie symmetrically left and right of a point above them. Which statement follows?

Public practice checks a specific claim. It does not establish independent mastery.

Explain why a negative test charge reverses its force but does not reverse the source field.

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

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