Reconstruct a source from explicitly modeled S–P ranges
P and S waves travel at different speeds, so their arrival-time difference can constrain distance under an assumed propagation model. In a homogeneous medium with speeds Vp and Vs, S−P=r(1/Vs−1/Vp). The source origin time cancels, but velocity structure and correct phase identification do not.
Learning outcome: Reconstruct ranges from the generated time differences and recover x/y from squared differences. Compare projected and slanted distances. State how an unknown depth or layered velocities would alter the inference.
Starting recap
Keep map geometry, relative displacement, source magnitude and conditional hazard evidence distinct. A model probability is not a deterministic forecast.
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For source (20,20) km at 10 km depth, ranges are 30,√2100,√2100 km. S−P times are about 3.57143,5.45545,5.45545 s. The squared-range differences recover x=y=20 km; the nearest horizontal radius is √800≈28.2843 km, not 30.
Open the experimentPredict
Why is an epicentral map circle smaller than a hypocentral range for a source below the surface?
Experiment
Reconstruct ranges from the generated time differences and recover x/y from squared differences. Compare projected and slanted distances. State how an unknown depth or layered velocities would alter the inference.
Reconstruct a supplied source from three ideal S−P ranges
Worked teaching model · synthetic values · Invented homogeneous medium Vp 6, Vs 3.5 km/s, known source depth 10 km. Stations at (0,0),(60,0),(0,60) km. S−P=r(1/Vs−1/Vp), with r hypocentral distance. Squared range differences recover x/y; surface circles require removal of the known depth term. No measured arrivals or real locator.
Reset keeps your prediction, captures and practice history.
S−P timing constrains a range only under a velocity and geometry model.
A circle drawn with hypocentral range on a flat map ignores source depth. The known-depth, noiseless packet admits a unique horizontal solution; real uncertainty, layered paths and unknown origin/depth require additional observations and inversion.
| Quantity | Value | Unit |
|---|---|---|
| Station 1 hypocentral range | 30 | km |
| Station 1 S−P time | 3.57142857 | s |
| Station 1 horizontal projected radius | 28.2842712 | km |
| Station 2 hypocentral range | 45.8257569 | km |
| Station 2 S−P time | 5.45544726 | s |
| Station 2 horizontal projected radius | 44.7213595 | km |
| Station 3 hypocentral range | 45.8257569 | km |
| Station 3 S−P time | 5.45544726 | s |
| Station 3 horizontal projected radius | 44.7213595 | km |
| Recovered east coordinate | 20 | km |
| Recovered north coordinate | 20 | km |
| Assumed depth | 10 | km |
| x | y |
|---|---|
| 0 | 0 |
| 60 | 0 |
| 0 | 60 |
S−P timing constrains a range only under a velocity and geometry model.
A circle drawn with hypocentral range on a flat map ignores source depth. The known-depth, noiseless packet admits a unique horizontal solution; real uncertainty, layered paths and unknown origin/depth require additional observations and inversion.
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Place the source at (0,0) with the same 10 km depth. What are the first station’s hypocentral range and horizontal projected radius?
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