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SCIENCE · INVESTIGATE AND EXPLAIN

Resolve effective normal force before interpreting slope resistance

A slope interpretation combines material strength, discontinuity orientation, water conditions and loading. Gravity has a component parallel to a potential sliding plane and a component normal to it. Pressure within connected water-filled fractures or pores can reduce the contact force available for friction, even if the assumed block weight is held fixed.

Learning outcome: Vary U at fixed angle, then angle at fixed U. Preserve force units and the separate cohesive/frictional terms. Identify which measured quantities and failure mechanisms would be needed before any actual site assessment.

Starting recap

Retain resource inventories, physical force and reaction boundaries, chronological alternatives and explicit decision constraints. Conditional teaching results do not certify actual site suitability.

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Try

At θ=30° and U=20 kN, total normal force is 86.6025 kN, effective normal 66.6025 kN, cohesive resistance 20 kN and friction 38.4530 kN. Driving force is 50 kN, giving ratio 1.16906. This is a conditional force balance, not clearance.

Open the experiment

Predict

Why can unchanged block weight and slope angle still produce a lower resistance ratio after a pore-pressure increase?

Experiment

Vary U at fixed angle, then angle at fixed U. Preserve force units and the separate cohesive/frictional terms. Identify which measured quantities and failure mechanisms would be needed before any actual site assessment.

Resolve gravity, pore force and friction on a plane

Worked teaching model · synthetic values · Original rigid block weight 100 kN, plane area 10 m², cohesion 2 kPa and friction angle 30°. Resistance = cA + (W cosθ − U)tanφ; driving = W sinθ. Positive effective normal force throughout controls. Static ideal model, no shaking, unsaturated suction, progressive failure or real slope clearance.

Reset keeps your prediction, captures and practice history.

Pore pressure reduces contact resistance even when the stipulated block weight is unchanged.

A ratio above one balances this ideal static force model only. It is not a safety factor certified for an actual site: discontinuities, parameter uncertainty, loading, groundwater dynamics and failure mechanisms remain unmeasured.

U normal outwardDownslopeθ = 30°; W = 100 kN vertically downwardOriginal geometry; force-arrow lengths are not magnitudes
Complete conditional quantities, with separate units
QuantityValueUnit
Total normal force86.60254kN
Pore-pressure resultant20kN
Effective normal force66.60254kN
Cohesive resistance20kN
Frictional resistance38.45299kN
Driving shear force50.00000kN
Resistance-to-driving ratio1.169060ratio

Original instructional packets and diagrams, not actual site measurements, legal limits or professional clearance.

Pore pressure reduces contact resistance even when the stipulated block weight is unchanged.

A ratio above one balances this ideal static force model only. It is not a safety factor certified for an actual site: discontinuities, parameter uncertainty, loading, groundwater dynamics and failure mechanisms remain unmeasured.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

1. Define the evidence and process

A slope interpretation combines material strength, discontinuity orientation, water conditions and loading. Gravity has a component parallel to a potential sliding plane and a component normal to it. Pressure within connected water-filled fractures or pores can reduce the contact force available for friction, even if the assumed block weight is held fixed.

2. Connect mechanism, geometry and boundary

For the original rigid block, weight W is 100 kN, plane area A is 10 m², cohesion c is 2 kPa and friction angle φ is 30°. At plane angle θ, driving shear is W sinθ and total normal force is W cosθ. Subtract the pore-pressure resultant U before applying friction: resistance = cA + (W cosθ−U)tanφ. A pressure in kPa becomes a force only after multiplication by area.

The ratio of resisting to driving force describes this static idealization. Increasing U at fixed geometry lowers resistance; steepening the plane both increases driving shear and reduces the gravity-derived normal force. All supported settings retain positive effective normal force, so the model does not silently extend a friction law into a separated contact.

Rock falls, slides, flows and creep involve different geometries and mechanisms; discontinuities, rainfall, thaw and shaking can alter them. A number above one here is not a certified real-site safety margin. Unknown strength, transient groundwater, progressive failure, three-dimensional geometry and dynamic loading remain outside the packet. There is no field access, slope loading or drainage intervention.

3. Reconstruct the worked packet

At θ=30° and U=20 kN, total normal force is 86.6025 kN, effective normal 66.6025 kN, cohesive resistance 20 kN and friction 38.4530 kN. Driving force is 50 kN, giving ratio 1.16906. This is a conditional force balance, not clearance.

4. Predict and investigate

Predict first: Why can unchanged block weight and slope angle still produce a lower resistance ratio after a pore-pressure increase?

Vary U at fixed angle, then angle at fixed U. Preserve force units and the separate cohesive/frictional terms. Identify which measured quantities and failure mechanisms would be needed before any actual site assessment.

5. Test changed evidence

Apply the evidence to a changed case

At θ=30° with U=0, compare the ratio with the worked wet-pressure case.

Retain the evidence frame, calculations and assumptions before opening public feedback.

Compare a worked response

Normal force is 50√3 kN and friction exactly 50 kN, so total resistance is 70 kN and ratio 1.4. Raising U to 20 reduces friction by 20/√3 kN and the ratio to about 1.16906; the stipulated weight did not change.

6. Retain a bounded decision

Preserve the first plan, source identity, original observations, units and competing interpretations. All numerical packets and diagrams in this category are invented teaching cases, not measured site conditions. Retain earlier actual USGS archives separately; do not merge unrelated sites into an invented actual history. Human review, unfamiliar transfer and any chosen supervised practical pathway remain separate. No mining, treatment, slope access or environmental clearance is authorized by these exercises.

Mechanism reference, checked 30 October 2026. Original prose, calculations, questions and diagrams.

Apply

Which force enters the friction term in this model?

Public practice checks a specific claim. It does not establish independent mastery.

At θ=30° with U=0, compare the ratio with the worked wet-pressure case.

Continue

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