Propagate a calibration interval without inventing a fossil date
Molecular differences can help estimate divergence time only through a model connecting change, rate and time. Under a strict equal-rate clock, two lineages diverging for time t accumulate pairwise expected divergence d=2rt. The factor two represents both lineages, not an arbitrary correction.
Learning outcome: Compare half-width0,2 and4 at target0.06. Reconstruct both rate and time bounds, then explain why a fossil known only to be at least8 Myr old does not justify the symmetric8–12 Myr interval.
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Reconstruct character-based relationships, preserve topological and sampling uncertainty, and distinguish lineage, species and detection measures of diversity.
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Reference0.04 and calibration8–12 Myr give rate bounds0.04/(2×12)=0.0016667 to0.04/(2×8)=0.0025 substitutions/site/Myr/lineage. Target0.06 then gives12–18 Myr, nominal15 Myr.
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Does an older calibration imply a faster rate or a slower rate for the same reference divergence?
Experiment
Compare half-width0,2 and4 at target0.06. Reconstruct both rate and time bounds, then explain why a fossil known only to be at least8 Myr old does not justify the symmetric8–12 Myr interval.
Propagate a calibration interval without treating it as certainty
Worked teaching model · synthetic values · Strict equal-rate two-lineage clock d=2rt. Reference divergence0.04 with calibration time10±b million years sets r interval. Target divergence exact for this conditional exercise; rate variation, topology, saturation and fossil-assignment error are excluded.
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A rate derived from an older calibration is smaller, so the same target divergence implies an older split.
These are monotonic input bounds, not a confidence interval. Two lineages contribute to pairwise divergence. A fossil minimum alone is not a symmetric calibration interval; rate shifts, saturation and uncertain placement can invalidate this strict-clock calculation.
| Quantity | Value | Unit |
|---|---|---|
| Calibration rate lower | 0.001666667 | substitutions/site/Myr/lineage |
| Calibration rate upper | 0.002500000 | substitutions/site/Myr/lineage |
| Target time lower | 12 | Myr |
| Target time upper | 18.00000 | Myr |
| Target nominal time | 15 | Myr |
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A rate derived from an older calibration is smaller, so the same target divergence implies an older split.
These are monotonic input bounds, not a confidence interval. Two lineages contribute to pairwise divergence. A fossil minimum alone is not a symmetric calibration interval; rate shifts, saturation and uncertain placement can invalidate this strict-clock calculation.
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Using reference divergence0.04 and calibration8–12 Myr, find the target-time interval for divergence0.08.
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