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SCIENCE · INVESTIGATE AND EXPLAIN

Integrate material resistance without confusing graph slopes

Resistivity describes a specified material state; resistance also depends on geometry.

Learning outcome: Compare uniform and linearly varying resistivity with the same rho0. Derive the cumulative voltage curve, then differentiate it. Predict both graph slopes. Finally use the supplied temperature and nonlinear packets to identify where a fixed-parameter ohmic model is no longer appropriate.

Starting recap

Integrate current or resistance, preserve node topology and derive transient state with a signed energy account.

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Try

For rho0 = 2 micro-ohm m, alpha = 1, A = 1 mm² and L = 1 m, R = 3 ohm. At 10 V, I = 10/3 A. The I-versus-V slope is 1/3 A/V; local field grows from 20/3 to 40/3 V/m while its integrated drop remains 10 V.

Open the experiment

Predict

An I-versus-V graph has slope 0.25 A/V for a fixed ohmic component. What is its resistance?

Experiment

Compare uniform and linearly varying resistivity with the same rho0. Derive the cumulative voltage curve, then differentiate it. Predict both graph slopes. Finally use the supplied temperature and nonlinear packets to identify where a fixed-parameter ohmic model is no longer appropriate.

Integrate a spatially varying resistivity

Worked teaching model · synthetic values · Uniform area 1 mm² and length 1 m; rho(x) = rho0(1 + alpha x/L). Maintained 10 V, steady current, prescribed local temperature/material state. No self-heating feedback solved. Material resistivity is not the same quantity as whole-object resistance.

Reset keeps your prediction, captures and practice history.

Cumulative resistor potential drop

potential drop (V)distance (m)01100

Axes rescale independently. Curves join sampled coordinates; a joining segment is not additional measured evidence. Read physical units rather than screen angles or apparent slopes.

Cumulative resistor potential drop: numerical coordinates
distance (m)potential drop (V)
00
0.01666670.112037
0.03333330.225926
0.050.341667
0.06666670.459259
0.08333330.578704
0.10.7
0.1166670.823148
0.1333330.948148
0.151.075
0.1666671.2037
0.1833331.33426
0.21.46667
0.2166671.60093
0.2333331.73704
0.251.875
0.2666672.01481
0.2833332.15648
0.32.3
0.3166672.44537
0.3333332.59259
0.352.74167
0.3666672.89259
0.3833333.04537
0.43.2
0.4166673.35648
0.4333333.51481
0.453.675
0.4666673.83704
0.4833334.00093
0.54.16667
0.5166674.33426
0.5333334.5037
0.554.675
0.5666674.84815
0.5833335.02315
0.65.2
0.6166675.3787
0.6333335.55926
0.655.74167
0.6666675.92593
0.6833336.11204
0.76.3
0.7166676.48981
0.7333336.68148
0.756.875
0.7666677.07037
0.7833337.26759
0.87.46667
0.8166677.66759
0.8333337.87037
0.858.075
0.8666678.28148
0.8833338.48981
0.98.7
0.9166678.91204
0.9333339.12593
0.959.34167
0.9666679.55926
0.9833339.7787
110
Calculated values under the declared model
QuantityValueUnit
Integrated resistance3ohm
Steady current3.33333A
Slope of I versus applied voltage0.333333A/V
Slope of voltage versus I3V/A
Local field at source end6.66667V/m
Local field at far end13.3333V/m

A constant current can coexist with a varying local electric field when resistivity changes along a uniform section.

Add infinitesimal series drops: dV = I rho(x) dx/A and R = integral rho(x) dx/A. The I-versus-V slope is conductance, so resistance is its reciprocal. These parameters describe a fixed material/temperature state; ordinary ohmic behavior at fixed temperature does not imply temperature-independent resistivity in all circumstances.

Derive before checking. Retain contrasting captures and explain one assumption that could fail; calculated evidence is not actual laboratory work.

A constant current can coexist with a varying local electric field when resistivity changes along a uniform section.

Add infinitesimal series drops: dV = I rho(x) dx/A and R = integral rho(x) dx/A. The I-versus-V slope is conductance, so resistance is its reciprocal. These parameters describe a fixed material/temperature state; ordinary ohmic behavior at fixed temperature does not imply temperature-independent resistivity in all circumstances.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Separate material from object

Resistivity describes a specified material state; resistance also depends on geometry. For a uniform segment, R = rho L/A. For uniform area but varying rho(x), a small series element contributes dR = rho(x) dx/A, so total R is its length integral. In steady state, the same current passes each section even though local field and voltage gradient can vary.

Carry the spatial integral

With rho(x) = rho0(1 + alpha x/L), integration gives R = rho0 L(1 + alpha/2)/A. The potential drop from 0 to x is I rho0[x + alpha x²/(2L)]/A. Differentiating this drop recovers the local field I rho(x)/A; integrating it over the full resistor recovers the applied voltage.

Use the axes to interpret a slope

For a fixed ideal ohmic resistance, I = V/R. Thus a graph with I vertically and V horizontally has slope 1/R; a V-versus-I graph has slope R. In a changed supplied non-ohmic law V = (2 ohm)I + (1 ohm/A²)I³, the secant V/I and differential dV/dI differ: at I = 1 A they are 3 ohm and 5 ohm. Neither can be silently treated as a single constant resistance over every current.

Qualify the temperature idealization

The constant-resistance model holds material conditions fixed. Ordinary metals often increase resistivity as temperature rises, and Joule heating can alter the operating state. Ohmic response at a fixed temperature does not establish temperature-independent resistivity under all conditions. We interpret the framework’s ideal constant-parameter statement as a model restriction, not a universal material law. For a supplied rho(T) = rho_ref[1 + 0.004(T − Tref)] with temperatures in kelvin differences, a 50 K rise increases resistance by 20% at unchanged geometry; the ideal unchanged-R prediction then fails.

Worked original case

For rho0 = 2 micro-ohm m, alpha = 1, A = 1 mm² and L = 1 m, R = 3 ohm. At 10 V, I = 10/3 A. The I-versus-V slope is 1/3 A/V; local field grows from 20/3 to 40/3 V/m while its integrated drop remains 10 V.

Investigation

Compare uniform and linearly varying resistivity with the same rho0. Derive the cumulative voltage curve, then differentiate it. Predict both graph slopes. Finally use the supplied temperature and nonlinear packets to identify where a fixed-parameter ohmic model is no longer appropriate.

Changed-case practice

Try a new practice case

Let rho0 = 3 micro-ohm m and alpha = 2 with the stated 1 m length and 1 mm² area. What is R in ohms?

This public, unsaved check is not a secure assessment. Explain the source integral, symmetry or charge boundary in the retained course evidence workspace.

Sources and evidence boundary

Original teaching checked 31 October 2026 against the current official framework, Unit 11 and OpenStax resistivity and resistance. All diagrams and numerical records are virtual, supplied or generated. No physical wiring, battery connection, short circuit, meter operation or electrical handling is requested. Public feedback and retained self-reports do not certify independent reasoning, actual laboratory participation or institutional credit.

Apply

An I-versus-V graph has slope 0.25 A/V for a fixed ohmic component. What is its resistance?

Public practice checks a specific claim. It does not establish independent mastery.

Which source, topology, initial condition or instrument assumption would invalidate this inference?

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