Learn

Learning preferences

Make learning more comfortable. Changes apply immediately.

Enlarges page content, including diagrams and their labels. You can also use your browser’s zoom.

Choose the colours that are easiest for you to distinguish. Applies to lesson diagrams and lab plots. Labels, shapes, hatching and line patterns also distinguish meanings. Source photographs and raw image brightness stay unchanged; mask-only views are available for image overlays.

ExampleComparisonSample link

Saved in this browser on this device. Preferences are separate from progress backups.

SCIENCE · INVESTIGATE AND EXPLAIN

Reconcile coaxial volume charge with piecewise field

Use enclosed area, not radial thickness, in a cylindrical charge account.

Learning outcome: Compare shell charges−2,−1 and+2 nC/m. Derive each enclosed-charge branch before plottingE. Check continuity at radii 1 and 2, then compare a point inside the core, inside the shell and outside both. State why this infinite insulating model is not a finite conducting cable calculation.

Starting recap

Choose source and observer coordinates, integrate normalized charge, and justify symmetry before simplifying field or flux.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

The core carries+2 nC/m within radius 1 m and the shell carries−2 nC/m between radii 1 and 2 m. At r = 1.5 m, enclosed charge per length is 2−2(2.25−1)/3 = 7/6 nC/m, giving Er≈13.9806 N/C. Beyond radius 2 m the net enclosed charge per length is zero, so the ideal exterior field vanishes.

Open the experiment

Predict

At a radius between 1 and 2 m, which fraction of the uniform shell’s charge per length is enclosed?

Experiment

Compare shell charges−2,−1 and+2 nC/m. Derive each enclosed-charge branch before plottingE. Check continuity at radii 1 and 2, then compare a point inside the core, inside the shell and outside both. State why this infinite insulating model is not a finite conducting cable calculation.

Reconcile a coaxial piecewise field

Worked teaching model · synthetic values · Infinite insulating core radius 1 m carries +2 nC/m uniformly. Insulating shell from 1 to 2 m carries selected signed charge per length uniformly; no conductor redistribution. Cylindrical symmetry and infinite length are stipulated; finite-end fields omitted.

Reset keeps your prediction, captures and practice history.

Piecewise coaxial radial field

Er (N/C)radius (m)0335.95020

Axes rescale independently. Curves join sampled coordinates; a joining segment is not additional measured evidence. Read physical units rather than screen angles or apparent slopes.

Piecewise coaxial radial field: numerical coordinates
radius (m)Er (N/C)
00
0.051.79751
0.13.59502
0.155.39253
0.27.19004
0.258.98755
0.310.7851
0.3512.5826
0.414.3801
0.4516.1776
0.517.9751
0.5519.7726
0.621.5701
0.6523.3676
0.725.1651
0.7526.9627
0.828.7602
0.8530.5577
0.932.3552
0.9534.1527
135.9502
1.0533.0685
1.130.3943
1.1527.9005
1.225.5646
1.2523.3676
1.321.2936
1.3519.3288
1.417.4615
1.4515.6817
1.513.9806
1.5512.3506
1.610.7851
1.659.27806
1.77.82446
1.756.41968
1.85.05966
1.853.74076
1.92.45975
1.951.2137
20
2.050
2.10
2.150
2.20
2.250
2.30
2.350
2.40
2.450
2.50
2.550
2.60
2.650
2.70
2.750
2.80
2.850
2.90
2.950
30
Calculated values under the declared model
QuantityValueUnit
Core charge per length2nC/m
Shell charge per length-2nC/m
Enclosed charge per length1.16667nC/m
Radial field13.9806N/C
Exterior total charge per length0nC/m

Zero exterior field does not require zero fields between oppositely charged regions.

The shell fraction depends on area(r²−1)/(4−1), not radial thickness. For a=−2 the exterior field vanishes, yet the positively charged core still produces a nonzero internal field.

Derive before checking. Retain contrasting captures and explain one assumption that could fail; calculated evidence is not actual laboratory work.

Zero exterior field does not require zero fields between oppositely charged regions.

The shell fraction depends on area(r²−1)/(4−1), not radial thickness. For a=−2 the exterior field vanishes, yet the positively charged core still produces a nonzero internal field.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Declare infinite cylindrical symmetry

The core and shell extend indefinitely along a shared axis, and their volume densities are uniform within each region. Rotational and translational symmetry makeE radial and constant on the curved wall of a coaxial Gaussian cylinder. End-cap normals are axial, so their flux is zero. A finite object would have edge fields absent from this model.

Use charge per length consistently

The core contains 2 nC per metre across area pi×1², and the shell occupies area pi(2²−1²). For r≤1, enclosed line charge is 2r² nC/m. For 1≤r≤2 it is 2+lambda_shell(r²−1)/3. Outside 2 it is 2+lambda_shell. The coefficient formulas use numerical metre coordinates with the fixed stated radii.

Derive the radial field

For Gaussian lengthell, flux isE(2pi r ell) and enclosed charge islambda_enclosed ell. Cancellingell givesE = lambda_enclosed/(2pi epsilon 0 r) = 2k lambda_enclosed/r. The signed line charge determines inward or outward direction. The core center limit is zero rather than a division-by-zero evaluation.

Interpret cancellation locally

Equal opposite total line charges produce zero exterior field, but an interior Gaussian surface can still enclose positive charge. Thus external shielding in this ideal distribution does not imply every region is field-free. The materials here are insulating; if they were conductors, charge redistribution and zero field inside conductor material would impose different constraints.

Worked original case

The core carries+2 nC/m within radius 1 m and the shell carries−2 nC/m between radii 1 and 2 m. At r = 1.5 m, enclosed charge per length is 2−2(2.25−1)/3 = 7/6 nC/m, giving Er≈13.9806 N/C. Beyond radius 2 m the net enclosed charge per length is zero, so the ideal exterior field vanishes.

Investigation

Compare shell charges−2,−1 and+2 nC/m. Derive each enclosed-charge branch before plottingE. Check continuity at radii 1 and 2, then compare a point inside the core, inside the shell and outside both. State why this infinite insulating model is not a finite conducting cable calculation.

Public numerical transfer practice

Try a new practice case

For shell charge−1 nC/m, what is Er at radius 3 m in N/C?

This public, unsaved check is not a secure assessment. Explain the source integral, symmetry or charge boundary in the retained course evidence workspace.

Sources and evidence boundary

Original cases and teaching checked 30 October 2026 against the current official calculus-based electricity and magnetism framework and OpenStax electric fields. All displayed records are generated or supplied, not learner measurements. No charging, mains connection, high-voltage equipment, physical circuit or material handling is requested. Public feedback and retained self-reports are practice evidence, not independent mastery, performed laboratory time or AP authorization.

Apply

At a radius between 1 and 2 m, which fraction of the uniform shell’s charge per length is enclosed?

Public practice checks a specific claim. It does not establish independent mastery.

Which source, boundary or independence assumption would have to change before the conclusion changes?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

Save a science backup or import one

Science work is stored locally in this browser, separately from mathematics and AI. It does not sync automatically. Use this science-only backup; this checkout's older all-subject export does not include science.

A legacy file is available only when the complete snapshot fits the 36 MB limit. For larger snapshots, prepare a complete file set below; never discard notebooks to make a smaller file.

Matching imported notebook drafts replace their current drafts. Omitted lessons and known first attempts remain. Export your current work first if you want to retain both drafts.

Complete file sets and course backups

A file set can hold more work than one science file. Keep its manifest and every part together. Each file is limited to 36 MB. This format needs this version of LearnAI or a compatible newer version; older versions can use only the legacy single-file backup above.

The set includes every saved science course and global continuation at this moment. Later edits need a new export. A conflicting tab exports its own visible work, which may differ from saved work in another tab.

0 file(s) selected. File order and filenames do not determine identity. Missing, changed or conflicting parts block the entire restore; no good part is applied by itself.

Science storage: loading. No account or remote computation is required.