Source-to-practice auditSchool geometry objective evidence
All 43 numbered HSG objectives across CO, SRT, C, GPE, GMD and MG, including (+). SRT.A.1 includes both lettered subparts. Evidence audit of registered teaching and public tasks; not state graduation, AP alignment, independent assessment or mastery certification.
These are content-evidence judgments, not mastery badges. Direct task evidence does not establish a complete course, independent assessment or preparation for a particular examination. Row counts may group related sub-objectives and must not be read as a coverage percentage.
43 of 43 objective rows shown.
HSG-CO.A.1 · Direct task evidence
Precise basic geometric definitions
Precise segment, ray, angle, circle/disk, perpendicular and parallel definitions are taught and repaired with explicit counterexamples; coplanarity, distinctness and arc ambiguity are stated.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.A.1
HSG-CO.A.2 · Direct task evidence
Transformations as functions and invariant comparisons
Whole-plane motion functions are compared with a horizontal stretch using arbitrary coordinate differences and a concrete angle failure. Intermediate traces distinguish composition order from rigidity.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.A.2
HSG-CO.A.3 · Direct task evidence
Symmetries of quadrilaterals and regular polygons
School constructions and exclusion arguments cover non-square rectangles, generic parallelograms, isosceles and generic trapezoids, and regular polygons, with square/rhombus exceptions and completeness of symmetry lists.
What this judgment means
The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Find the complete symmetry set — Geometric definitions, motion witnesses and theorem proofs
- How many reflection axes does a non-square rectangle have?Automatically checked response; reasoning still matters
- For A=(0,0),B=(5,0),C=(7,3),D=(2,3), construct a nonidentity rotational symmetry and explain why this parallelogram has no reflection symmetry.Written reasoning: review required
- Compare trapezoid T with vertices (−3,0),(3,0),(2,2),(−2,2) and U with vertices (0,0),(6,0),(4,2),(1,2). Identify all reflection symmetries and nonidentity rotations. Here trapezoid means exactly one parallel side pair.Written reasoning: review required
- For a regular hexagon, describe all rotations and reflection axes and justify that there are no additional ones.Written reasoning: review required
- A learner claims every diagonal of every rectangle is a reflection axis. Refute the claim using vertices (0,0),(4,0),(4,2),(0,2), and state when the diagonal claim does hold.Written reasoning: review required
Construct witnesses and justify geometric conclusions — Geometric definitions, motion witnesses and theorem proofs
Use relations without assuming rotations commute with reflections — Abstract algebra I: groups and symmetry
Link to HSG-CO.A.3
HSG-CO.A.4 · Direct task evidence
Geometric definitions of rigid motions
Translations use one common displacement, rotations a center/angle and fixed radius, and reflections a perpendicular-bisector line with fixed points. Written rules and inverse procedures apply these whole-plane definitions.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.A.4
HSG-CO.A.5 · Direct task evidence
Draw images and determine a motion sequence
Graph-paper image construction and the bounded motion explorer require ordered operations and complete labeled triangle images; practice recovers and repairs sequences with explicit intermediate coordinates.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Construct and verify a motion witness — Geometric definitions, motion witnesses and theorem proofs
- Map A=(0,0),B=(2,0),C=(0,3) to A′=(−1,5),B′=(−1,7),C′=(−4,5) with an explicit rigid sequence. Verify every vertex.Written reasoning: review required
- Map A=(0,0),B=(3,0),C=(0,2) to A′=(1,1),B′=(4,1),C′=(1,−1). Give a witness and explain why translations and rotations alone cannot produce this labeled correspondence.Written reasoning: review required
- A proposed witness for the previous target translates by (1,1) first and then reflects in the x-axis. Compute all images and repair it without changing the operation order.Written reasoning: review required
Construct witnesses and justify geometric conclusions — Geometric definitions, motion witnesses and theorem proofs
- Map A=(1,0),B=(4,0),C=(1,2) to P=(2,5),Q=(2,2),R=(0,5) using a reflection followed by a quarter-turn and a translation. Verify all three points, write the total coordinate function and prove it preserves every distance.Written reasoning: review required
Move a figure without changing its shape — Euclidean and coordinate geometry foundations
Link to HSG-CO.A.5
HSG-CO.B.6 · Direct task evidence
Use rigid motions to decide congruence
Learners supply a rigid witness for complete figures or prove impossibility using corresponding distance/orientation obstructions. Affine segment/interior arguments extend vertex matching to the full triangle.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Construct and verify a motion witness — Geometric definitions, motion witnesses and theorem proofs
- Map A=(0,0),B=(3,0),C=(0,2) to A′=(1,1),B′=(4,1),C′=(1,−1). Give a witness and explain why translations and rotations alone cannot produce this labeled correspondence.Written reasoning: review required
- A rectangle with vertices (0,0),(2,0),(2,1),(0,1) is claimed congruent, with corresponding corners, to (0,0),(4,0),(4,1),(0,1). Give an obstruction. Does preserving right angles suffice for congruence?Written reasoning: review required
Define triangle congruence through a witness — Geometric definitions, motion witnesses and theorem proofs
- A rigid motion sends the three vertices of a triangle to three target vertices in order. Explain why it sends the complete triangular region onto the target region, and why arbitrary three-point functions would not suffice.Written reasoning: review required
- For A=(0,0),B=(4,0),C=(0,3) and P=(1,1),Q=(1,5),R=(−2,1), construct the correct correspondence and witness. Explain why A→P,B→R,C→Q is impossible.Written reasoning: review required
Move a figure without changing its shape — Euclidean and coordinate geometry foundations
Match triangles with sufficient evidence — Euclidean and coordinate geometry foundations
Link to HSG-CO.B.6
HSG-CO.B.7 · Direct task evidence
Triangle congruence equivalence from motions
The explicit two-way statement is proved: rigid congruence preserves corresponding sides and angles; derived SSS supplies the converse, making the supplied angle data redundant. Nondegeneracy and correspondence are explicit.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.B.7
HSG-CO.B.8 · Direct task evidence
Derive ASA, SAS and SSS from rigid motions
SSS follows from aligned distance equations and reflection; SAS from same-side ray/distance uniqueness; ASA from two ray intersections. Existence is distinguished from uniqueness, and SSA has a concrete counterexample.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.B.8
HSG-CO.C.9 · Direct task evidence
Prove line, angle and bisector theorems
New vertical/parallel-angle proofs and the converse state the Euclidean uniqueness assumption and track rays. The existing school perpendicular-bisector locus proof supplies both directions of equidistance, retained below.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.C.9
HSG-CO.C.10 · Direct task evidence
Prove triangle angle, midpoint and median results
Learner proofs cover triangle angle sum, isosceles base angles, midsegment direction/half-length and general median concurrence with the 2:1 division ratio; coordinates remain arbitrary in the general arguments.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.C.10
HSG-CO.C.11 · Direct task evidence
Prove parallelogram and rectangle properties
General parallelogram proofs establish opposite sides/angles and diagonal bisection in both directions. Equal-diagonal rectangle equivalence is proved within parallelograms, with a trapezoid counterexample when that hypothesis is omitted.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.C.11
HSG-CO.D.12 · Direct task evidence
Execute and justify basic constructions
Executable compass/straightedge steps cover copying lengths/angles, segment/angle bisection, on-line and off-line perpendiculars, and an external-point parallel. Ideal folding supplies a second tool method; steps, intersection choices, strict radius conditions and correctness proofs are required.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.D.12
HSG-CO.D.13 · Direct task evidence
Construct regular figures inscribed in a circle
Learners construct all three requested inscribed figures: radius-stepped hexagon with closure proof, alternate-vertex equilateral triangle, and square from perpendicular diameters. Regularity and construction-error diagnosis are explicit.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-CO.D.13
HSG-SRT.A.1 · Direct task evidence
Verify dilation of lines and segments (a and b)
An off-origin center explorer and written image-line/segment constructions verify both numbered subparts. General displacement proofs cover full lines, vertical lines, positive length ratios and the k=1 coincident-line exception.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.A.1
HSG-SRT.A.2 · Direct task evidence
Similarity transformations and triangle correspondence
Learners construct and verify similarities, derive common side ratios and angle preservation, reject a one-angle claim and handle reversed orientation with an explicit reflection.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Construct a similarity and derive AA — Geometric definitions, motion witnesses and theorem proofs
- Construct a similarity taking A=(0,0), B=(3,0), C=(0,4) to P=(2,−1), Q=(8,−1), R=(2,7). Verify all three vertices and explain what happens to sides and angles.Written reasoning: review required
- Two right triangles have legs (3,4) and (3,5). Does their common right angle prove similarity? Give a decisive test and explain why AA is stronger.Written reasoning: review required
- A=(0,0), B=(2,0), C=(0,1) and P=(4,2), Q=(0,2), R=(4,4) are proposed corresponding vertices. Find a similarity witness and discuss why a positive dilation and translations alone cannot suffice.Written reasoning: review required
Scale lengths, areas and arguments — Euclidean and coordinate geometry foundations
Similarities and the hierarchy of invariants — Axiomatic Euclidean and non-Euclidean geometry
Link to HSG-SRT.A.2
HSG-SRT.A.3 · Direct task evidence
Derive AA using similarity transformations
AA is derived by rigid side alignment, same-half-plane reflection, positive dilation and uniqueness of the two endpoint rays. The proof uses established angle preservation rather than assuming AA.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.A.3
HSG-SRT.B.4 · Direct task evidence
Proportional cuts and similarity proof of Pythagoras
The general parallel-cut theorem and converse are proved with positive interior ratios and an auxiliary parallel. Altitude similarities derive the squared-leg identities and Pythagoras; the earlier distance formula has an independent dissection premise.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Use proportional cuts and altitude similarity — Geometric definitions, motion witnesses and theorem proofs
- Prove that a line parallel to BC meeting the interiors of AB and AC at D,E cuts those sides proportionally, both AD/AB=AE/AC and AD/DB=AE/EC.Written reasoning: review required
- Suppose D,E lie inside AB,AC and AD/AB=AE/AC. Prove DE parallel to BC without citing the converse as an axiom.Written reasoning: review required
- Let ABC be right at C, and let CD be perpendicular to hypotenuse AB. Put AD=p, DB=q, AB=c, AC=b, BC=a. Derive b²=cp, a²=cq and then Pythagoras from AA.Written reasoning: review required
- A right triangle has hypotenuse 25 and one leg 15. Find its other leg, the two hypotenuse projections and its altitude. Explain why these formulas cannot be copied to an arbitrary oblique triangle.Written reasoning: review required
Construct witnesses and justify geometric conclusions — Geometric definitions, motion witnesses and theorem proofs
Scale lengths, areas and arguments — Euclidean and coordinate geometry foundations
Connect right angles with squared lengths — Euclidean and coordinate geometry foundations
Link to HSG-SRT.B.4
HSG-SRT.B.5 · Direct task evidence
Use triangle criteria in problems and proofs
Matching-side computation, isosceles proof and midsegment proof exercise both numerical and geometric uses. Direct evidence remains public practice, not independent mastery.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.B.5
HSG-SRT.C.6 · Direct task evidence
Derive acute-angle ratios from similarity
Prose derives scale independence by AA and the written ratio-proof asks learners to explain it; numerical sine and identity tasks connect the definition to calculation.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.C.6
HSG-SRT.C.7 · Direct task evidence
Complementary sine and cosine
The diagram activity exchanges the two acute angles and opposite/adjacent roles, while complement identifies the resulting identity. A fresh written general explanation would strengthen assessment sampling.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.C.7
HSG-SRT.C.8 · Direct task evidence
Solve applied right-triangle problems
The mast task states vertical/level assumptions and the prose diagnoses missing observer height. Right-triangle length tasks supply Pythagorean practice; wider calculator transfer is still desirable.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.C.8
HSG-SRT.D.9 · Direct task evidence
Derive triangle area with an altitude (+)
A learner altitude construction derives the area formula for acute, right and obtuse included angles, using the full baseline and positive supplementary-angle height. Coordinate examples and a fresh exact task check the mechanism.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.D.9
HSG-SRT.D.10 · Direct task evidence
Prove and use the sine and cosine laws (+)
Learner proofs derive the sine law from cyclic altitude-area expressions and the cosine law from coordinates, with nondegenerate conditions and obtuse signs. Fresh survey/SSA work checks use, both inverse-sine branches and rounded calculator evidence.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.D.10
HSG-SRT.D.11 · Direct task evidence
Use general-triangle laws for measurements (+)
Exact non-right side calculations, feasibility checks and SSA ambiguity exercise the laws; path-distance prose supplies context. Add unfamiliar surveying or force data for broader transfer without replacing existing lessons.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-SRT.D.11
HSG-C.A.1 · Direct task evidence
Prove all circles are similar
An explicit translation/dilation map between arbitrary positive-radius circles is proved onto by constructing every target point’s inverse image. Radius-zero and empty loci are distinguished.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-C.A.1
HSG-C.A.2 · Direct task evidence
Circle angle, chord and tangent relationships
New inscribed-angle addition/subtraction proofs select the arc avoiding the vertex, cyclic proofs use complementary arcs, and tangent-angle proofs derive the minor/major half-difference relationship. Existing chord and tangent-radius evidence is retained.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-C.A.2
HSG-C.A.3 · Direct task evidence
Triangle circles and cyclic quadrilateral proofs
Circumcircle and incircle construction steps are justified by both equidistance loci. Interior-bisector existence, obtuse-angle foot cases and side-segment contact are established; convex cyclic-quadrilateral angle properties have explicit proofs.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-C.A.3
HSG-C.A.4 · Direct task evidence
Construct external tangents (+)
The diameter-circle construction locates both external tangent contacts and proves correctness, existence and completeness. On-circle and interior cases explicitly require a different construction or have no tangents.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-C.A.4
HSG-C.B.5 · Direct task evidence
Similarity, radian arcs and sector area
Finite chord sums and their limiting lengths establish similarity-based arc scaling; radian measure is the radius-independent ratio. Rational sector partitions and bounding limits derive area for arbitrary angles, with degree/radian and multi-turn distinctions.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-C.B.5
HSG-GPE.A.1 · Direct task evidence
Derive and recover circle equations
The arbitrary-center circle equation is derived from Pythagorean distance and reversed with nonnegative-root checks. Completing squares identifies center/radius and separates positive-circle, point and empty outcomes.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-GPE.A.1
HSG-GPE.A.2 · Direct task evidence
Derive a focus-directrix parabola
Prose derives the general axis-aligned equation and the task derives a fresh focus/directrix case, explicitly checking reversible squaring.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-GPE.A.2
HSG-GPE.A.3 · Direct task evidence
Derive focal ellipse and hyperbola equations (+)
Both ellipse and hyperbola equations are derived from focal sums/absolute differences and proved equivalent by sign-controlled reverse implications. Translated foci, both hyperbola branches and degenerate/empty parameter cases are exercised.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Derive the ellipse from its two foci — Geometric constructions, circle proofs and coordinate loci
- Derive x²/a²+y²/b²=1 from d₋+d₊=2a, where d₋=√((x+c)²+y²), d₊=√((x−c)²+y²), a>c>0 and b²=a²−c².Written reasoning: review required
- Prove the standard ellipse equation implies the original focal sum under a>c>0, b²=a²−c². Identify the sign check after squaring.Written reasoning: review required
- For distinct foci separated by 10, classify focal sums 8,10,14. Why does the middle case not allow division by positive b²?Written reasoning: review required
- Find the ellipse with foci (−1,3),(7,3) and sum 10. Verify (3,6) using the original distances.Written reasoning: review required
Derive both branches of a hyperbola — Geometric constructions, circle proofs and coordinate loci
- Derive x²/a²−y²/b²=1 from right-branch d₋−d₊=2a, with d₋=√((x+c)²+y²), d₊=√((x−c)²+y²), 0<a<c and b²=c²−a². Explain the left branch.Written reasoning: review required
- Prove that the full equation implies |d₋−d₊|=2a under 0<a<c,b²=c²−a². Include both branches and signs.Written reasoning: review required
- For foci (−3,0),(3,0), classify absolute differences 0,6,8 and compare with a difference strictly between 0 and 6.Written reasoning: review required
- Find the hyperbola with foci (1,−2),(11,−2) and absolute difference 6. Give vertices and show its asymptotes are not in the locus.Written reasoning: review required
Construct, prove and measure unfamiliar configurations — Geometric constructions, circle proofs and coordinate loci
Read conics from equations and geometric definitions — Trigonometry, polar geometry and precalculus representations
Conics as homogeneous quadratic geometry — Axiomatic Euclidean and non-Euclidean geometry
Link to HSG-GPE.A.3
HSG-GPE.B.4 · Direct task evidence
Coordinate proofs of geometric claims
General-coordinate diagonal bisection and triangle midsegment tasks require full hypotheses and interpretation, not only one numerical picture.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-GPE.B.4
HSG-GPE.B.5 · Direct task evidence
Prove and apply slope criteria
General direction/quarter-turn proofs establish both slope criteria and their converses. Learners construct through-point lines and handle vertical, horizontal and coincident cases instead of dividing by an undefined slope.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Prove and use coordinate line criteria — Geometric constructions, circle proofs and coordinate loci
Construct, prove and measure unfamiliar configurations — Geometric constructions, circle proofs and coordinate loci
Choose coordinates that expose the geometry — Euclidean and coordinate geometry foundations
- What is the slope of the line through (3,−2) and (3,5)?Automatically checked response; reasoning still matters
- For A=(0,0), B=(b,0), C=(u,v), b>0,v≠0, prove the segment joining the midpoints of AB and AC is parallel to BC and half as long without slopes.Written reasoning: review required
Measure vector alignment and projection — Trigonometry, polar geometry and precalculus representations
Link to HSG-GPE.B.5
HSG-GPE.B.6 · Direct task evidence
Divide a directed segment in a specified ratio
The non-midpoint internal ratio formula is derived from the whole-segment fraction and constructed with equal auxiliary steps and a parallel. Endpoint reversal and external extrapolation are separately checked.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Divide a directed segment in a chosen ratio — Geometric constructions, circle proofs and coordinate loci
- Derive P=(nA+mB)/(m+n) for AP:PB=m:n internally. State all positivity and ordering assumptions.Written reasoning: review required
- Using unmarked straightedge and compass, divide a given nonzero segment AB internally in the ratio 3:2. Prove the construction.Written reasoning: review required
- For A=(1,−2), B=(5,4), interpret P=A+(3/2)(B−A). Find P and unsigned AP:PB. Why does the internal section formula fail for that ratio?Written reasoning: review required
- For A=(−4,0), B=(8,6), P has AP:PB=2:1 internally. Find P, express it from B toward A, and diagnose using t=2/1.Written reasoning: review required
Construct, prove and measure unfamiliar configurations — Geometric constructions, circle proofs and coordinate loci
Choose coordinates that expose the geometry — Euclidean and coordinate geometry foundations
Betweenness, separation and Pasch — Axiomatic Euclidean and non-Euclidean geometry
Affine coordinates and barycentric reasoning — Axiomatic Euclidean and non-Euclidean geometry
Link to HSG-GPE.B.6
HSG-GPE.B.7 · Direct task evidence
Coordinate perimeter and area calculations
Supplied non-axis-aligned polygons require boundary distances, justified rectangle structure and triangle/rectangle area. Explicit decompositions and a derived perpendicular-height formula distinguish actual area from bounding boxes or signed cancellation.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Measure coordinate polygons with justified lengths — Geometric constructions, circle proofs and coordinate loci
- Rectangle vertices in order are A=(1,1), B=(4,5), C=(−8,14), D=(−11,10). Find its perimeter.Automatically checked response; reasoning still matters
- Find the area of the triangle with vertices (0,0),(4,2),(−2,6).Automatically checked response; reasoning still matters
- For A=(−2,1), B=(1,5), D=(−14,10), construct the fourth vertex C of a rectangle, then find area and perimeter with justification.Written reasoning: review required
- Derive the area |ps−qr|/2 of a triangle with side vectors u=(p,q),v=(r,s) from one vertex. Do not merely quote the formula.Written reasoning: review required
- A simple polygon has ordered vertices (0,0),(6,0),(6,4),(3,2),(0,4). Find its area by rectangle decomposition and identify its concave vertex.Written reasoning: review required
- A learner connects (0,0),(4,3),(4,0),(0,3) in that order and calls it a rectangle of area 12. Diagnose and supply a valid order and perimeter.Written reasoning: review required
Construct, prove and measure unfamiliar configurations — Geometric constructions, circle proofs and coordinate loci
Choose coordinates that expose the geometry — Euclidean and coordinate geometry foundations
Decompose a region without counting it twice — Euclidean and coordinate geometry foundations
Link to HSG-GPE.B.7
HSG-GMD.A.1 · Direct task evidence
Explain circle and elementary volume formulas
School-entry polygon bounds explain circumference and disk area; tiling and extrusion justify cylinders; squared similarity and converging inner/outer slabs derive pyramid and cone volume without calculus.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-GMD.A.1
HSG-GMD.A.2 · Direct task evidence
Cavalieri arguments for spheres and solids (+)
Every-height sphere/double-cone comparison derives sphere volume using Cavalieri. Explicit slab bounds and a finite-sample counterexample distinguish a limiting argument from checking a few slices.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Link to HSG-GMD.A.2
HSG-GMD.A.3 · Direct task evidence
Apply cylinder, pyramid, cone and sphere volumes
School-entry contextual calculations cover cylinders, pyramids, cones and spheres, with perpendicular height, material versus capacity, cubic units and bounded measurement uncertainty.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Solid geometry: sections, limits and design evidence — Sections, solid measures and geometric design
Choose and test a model for a measured object — Sections, solid measures and geometric design
- A square-based decorative pyramid has base side 12 cm and perpendicular height 5 cm. Find its external volume in cm³.Automatically checked response; reasoning still matters
- Synthetic radius measurements of a solid at heights 0,2,4,6 cm are 3,3,2,0 cm. Compare an ideal radius 3,height 6 cylinder with a cylinder of height 2 joined to a cone of height 4, both radius 3. Which better respects the measured taper, and what remains uncertain?Written reasoning: review required
- A synthetic sphere model has radius 3 cm and predicts 36πcm³. A displacement reading is 114±2 cm³, interpreted as inclusive bounds. Using 3.14159<π<3.14160, decide whether the prediction lies in the interval and what that does not prove.Written reasoning: review required
- A cylindrical container has external radius 5 cm and internal radius 4.8 cm, height 10 cm, with no bottom or lid in this idealized model. Determine material volume and explain whether external capacity is the right quantity.Written reasoning: review required
- A cone radius is bounded by[1.9,2.1]cm and height by[5.8,6.2]cm. Give exact volume bounds as multiples of π and explain why a midpoint calculation alone is insufficient.Written reasoning: review required
Derive the one-third volume factor — Sections, solid measures and geometric design
Relate simultaneous rates before substituting — Differential calculus: techniques and applications
Triple integrals in Cartesian, cylindrical and spherical coordinates — Multivariable calculus: geometry, change and accumulation
Link to HSG-GMD.A.3
HSG-GMD.B.4 · Direct task evidence
Relate sections and rotations to solids
Supplied equal-scale section and generating-region diagrams support plane identification, oblique-cut conditions, axis changes, holes and filled-region versus boundary rotation. General distance rules justify whole solids.
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The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
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Solid geometry: sections, limits and design evidence — Sections, solid measures and geometric design
Read a solid through its sections — Sections, solid measures and geometric design
Predict what a rotating region fills — Sections, solid measures and geometric design
- For the rectangle 0≤x≤3,0≤z≤5, compare rotation about the z-axis with rotation about the x-axis. Describe both solids and give the ratio of the second volume to the first.Written reasoning: review required
- Rotate the filled right triangle with vertices (0,0),(4,0),(0,6), using horizontal x and vertical z, about the z-axis. Derive the radius of the horizontal section at height z and identify the solid.Written reasoning: review required
- Rotate the filled right half-disk x≥0,x²+z²≤9 about the z-axis. Compare rotating only its semicircular arc.Written reasoning: review required
- A full disk x²+z²≤4 is rotated about its vertical diameter. A learner adds the swept volumes of its left and right halves. Diagnose the error and give the correct set description.Written reasoning: review required
Build volume from cross-sectional area — Integral calculus: accumulation, methods and applications
Count thin cylindrical layers — Integral calculus: accumulation, methods and applications
Link to HSG-GMD.B.4
HSG-MG.A.1 · Direct task evidence
Choose geometric models for physical objects
Learners compare cylinder and composite models against synthetic radius observations, identify residual mismatch, check displacement bounds and distinguish capacity from material. This supplies bounded modeling practice, not empirical validation or independent modeling proficiency.
What this judgment means
The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
Inspect the evidence
Solid geometry: sections, limits and design evidence — Sections, solid measures and geometric design
Choose and test a model for a measured object — Sections, solid measures and geometric design
- Synthetic radius measurements of a solid at heights 0,2,4,6 cm are 3,3,2,0 cm. Compare an ideal radius 3,height 6 cylinder with a cylinder of height 2 joined to a cone of height 4, both radius 3. Which better respects the measured taper, and what remains uncertain?Written reasoning: review required
- A synthetic sphere model has radius 3 cm and predicts 36πcm³. A displacement reading is 114±2 cm³, interpreted as inclusive bounds. Using 3.14159<π<3.14160, decide whether the prediction lies in the interval and what that does not prove.Written reasoning: review required
- A cylindrical container has external radius 5 cm and internal radius 4.8 cm, height 10 cm, with no bottom or lid in this idealized model. Determine material volume and explain whether external capacity is the right quantity.Written reasoning: review required
- A cone radius is bounded by[1.9,2.1]cm and height by[5.8,6.2]cm. Give exact volume bounds as multiples of π and explain why a midpoint calculation alone is insufficient.Written reasoning: review required
Choose ratios relative to an angle — Euclidean and coordinate geometry foundations
Relate simultaneous rates before substituting — Differential calculus: techniques and applications
Link to HSG-MG.A.1
HSG-MG.A.2 · Direct task evidence
Model density per area or volume
School-entry population per area and mass per volume tasks require explicit denominators, units and volume weighting; sheet area density is distinguished from volume density. Uniformity and synthetic-data limits remain explicit.
What this judgment means
The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
Inspect the evidence
Link to HSG-MG.A.2
HSG-MG.A.3 · Direct task evidence
Constrained geometric design
The school garden task constructs a perimeter-constrained area function and proves its attained maximum with feasible-domain exclusions. Calculus fence/box design gives optional depth, not a required entry route. The solid-design task also compares two feasible capacity-constrained boxes by material area and rechecks feasibility after a height-limit change; it does not claim a global optimum among all boxes.
What this judgment means
The inspected explanation and learner tasks address the named action. This is not a full-course or mastery judgment.
Inspect the evidence
Link to HSG-MG.A.3