Learn

Learning preferences

Make learning more comfortable. Changes apply immediately.

Enlarges page content, including diagrams and their labels. You can also use your browser’s zoom.

Choose the colours that are easiest for you to distinguish. Applies to lesson diagrams and lab plots. Labels, shapes, hatching and line patterns also distinguish meanings. Source photographs and raw image brightness stay unchanged; mask-only views are available for image overlays.

ExampleComparisonSample link

Saved in this browser on this device. Preferences are separate from progress backups.

Lesson 12 of 12

Construct a point and justify why it works

Separate a permitted construction procedure from its mathematical correctness.

Loading your saved responses…

On a narrow screen, scroll diagrams horizontally to read every label. Keyboard users can focus a diagram and use the arrow keys.

Try

Construct an equilateral triangle on a segment AB by drawing one circle centered at A through B and another centered at B through A. Either intersection C has AC=AB and BC=AB because both are radii. The equality is guaranteed by construction, not by measuring the finished triangle.

Predict

Predict what an unmarked straightedge can do. It draws a line through two distinct known points; it does not read lengths or angles. A compass transfers a radius. A construction consists of permitted steps; its proof explains why the resulting object has the desired properties.

Experiment

Use the diagram to plan a perpendicular bisector. Choose the same radius for both endpoint circles, greater than half AB, so there are two distinct intersections P,Q. Join P and Q. If the radius equals half AB there is only one touching point, so the line through two intersections cannot be drawn.

Construct a point and justify why it works: geometric diagramTwo equal circles centered on a horizontal segment intersect above and below it. The vertical line through their intersections crosses the segment at its midpoint.ABPQM
Equal-radius circles centered at A and B intersect at P and Q. Their common chord PQ is the perpendicular bisector of AB. The radius exceeds half AB; this is a construction diagram, not a measurement instruction.

Understand

Worked justification: P and Q are each equidistant from A and B because they lie on equal-radius circles. The locus of points equidistant from A,B is their perpendicular bisector. To justify that locus for a point P off line AB, let M be the midpoint. Congruent triangles AMP and BMP give equal angles at M; these angles are supplementary, so each is 90°. On line AB itself, only M is equidistant. Conversely a point on the perpendicular bisector gives congruent right triangles and equal distances; M is immediate. Thus the line PQ is the required bisector.

Invalid construction: choose different radii at A and B and assume the intersection points are equidistant from the endpoints. Each distance then equals a different radius; the justification fails even if the drawn line appears central.

Apply

For each written construction give the tools, centers, radius choices, intersection choice and joining line. Then prove the result using equal distances or congruence. When two intersections are possible, specify which one serves the intended internal angle or side of a line.

Continue

Depth: for an internal angle bisector, first mark equal distances OA=OB along its rays. Intersect equal-radius circles centered at A,B and choose the intersection opposite O across chord AB. Joining it to O bisects the angle by SSS. Later construction theory asks which exact lengths and angles are constructible; arbitrary angle trisection is not an operation these tools automatically provide.

Apply · explain · revise

Practice and reasoning

Drafts save locally as you type. Reveal worked solutions when useful; the site remembers that exposure. Automatic matches check the requested answer, while written arguments require review against the rubric.

Segment AB is 10 cm long. Equal-radius circles centered at A and B intersect twice only when their radius exceeds what value, in cm?

Integers, fractions and finite decimals are accepted. Expressions such as sqrt(2) are not parsed by this checker.

An equilateral triangle is constructed on a segment of length 6. What is the square of its altitude?

Integers, fractions and finite decimals are accepted. Expressions such as sqrt(2) are not parsed by this checker.

Which action is allowed with an unmarked straightedge?

Your response

For the perpendicular-bisector construction with equal-radius circles, why use the line joining their two intersections?

Your response

Construct the perpendicular bisector of a segment AB and justify it, including the radius condition.

Structure your argument and preserve revisions

These optional planning fields save locally. Recording your response saves an immutable copy of the argument and these fields. Older records may contain only first/latest responses; missing intermediate revisions are not reconstructed.

Each field allows 2,000 characters. Keep a specific claim, state where it applies, cite the facts you use, and explain what still needs checking. Blank fields are allowed and are not evidence of mastery.

Construct the internal bisector of an angle strictly between 0° and 180° and prove it using congruent triangles.

Structure your argument and preserve revisions

These optional planning fields save locally. Recording your response saves an immutable copy of the argument and these fields. Older records may contain only first/latest responses; missing intermediate revisions are not reconstructed.

Each field allows 2,000 characters. Keep a specific claim, state where it applies, cite the facts you use, and explain what still needs checking. Blank fields are allowed and are not evidence of mastery.

Reflect and continue

Before marking this lesson complete, explain one key idea without the worked solution and identify a condition that matters. Marking complete records participation, not independent mastery.