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Lesson 4 of 12

Locate triangle centers and test possible sides

Distinguish medians, bisectors and altitudes, and recognize degenerate side data.

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A triangle can have several useful centers. In the right triangle with vertices (0,0),(6,0),(0,6), the centroid is (2,2) while the circumcenter is (3,3). The diagram makes their separation visible; neither is simply “the center” without a definition.

Predict

Predict which construction answers each question. Medians meet at the centroid, which divides each median 2:1 from its vertex. Perpendicular bisectors meet at the circumcenter, equidistant from vertices. Internal angle bisectors meet at the incenter, equidistant from sides. Altitudes meet at the orthocenter. In an obtuse triangle, some centers lie outside it.

Experiment

Draw the midpoint of the hypotenuse in the diagram and join it to the opposite vertex. Locate the point two thirds along that median. Measure its coordinates using the stated scale, then verify them arithmetically. Separately test side triples 4,7,10 and 4,7,11 with strips or a sketch: equality at the largest side makes a straight configuration, not a triangle.

Locate triangle centers and test possible sides: geometric diagramA right isosceles triangle. A median joins its right-angle vertex to the midpoint of the hypotenuse. The centroid is two thirds along this median; the circumcenter is the midpoint itself.(0,0)(6,0)(0,6)G (2,2)O (3,3)
Right triangle with vertices (0,0), (6,0), (0,6), plotted with equal coordinate scales. G=(2,2) is the centroid; O=(3,3) is the circumcenter. They are different points.

Understand

Worked argument: for a nondegenerate triangle with two sides 6 and 10 and third side x, the strict triangle inequalities give x+6>10 and 6+10>x. Hence 4<x<16; the remaining inequality is then satisfied. Endpoints are excluded because they collapse the triangle into a line.

The circumcenter’s defining fact follows from a locus theorem: a point is equidistant from A,B exactly when it lies on their perpendicular bisector. Thus a point on the perpendicular bisectors of AB and AC has equal distances to all three vertices. Invalid proof: “All three bisectors look concurrent.” Equality of distances, not appearance, supplies the reasoning.

Apply

Name the center and the defining lines in each response. A median need not be perpendicular to its side, and an angle bisector need not bisect that side. When testing possible lengths, use strict inequalities and distinguish integer candidates from the full real interval.

Continue

Depth: derive the centroid coordinates by showing that the point averaging the three vertices divides each median in ratio 2:1. For circumcenters, use perpendicular-bisector equations; for a right triangle, the hypotenuse midpoint is equidistant from all vertices. The equalities coincide in an equilateral triangle, not in every triangle.

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Practice and reasoning

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A median has length 18 cm. How far is the centroid from its vertex, in cm?

Integers, fractions and finite decimals are accepted. Expressions such as sqrt(2) are not parsed by this checker.

Two sides are 5 and 9. How many integer lengths can the third side have in a nondegenerate triangle?

Integers, fractions and finite decimals are accepted. Expressions such as sqrt(2) are not parsed by this checker.

Which lines meet at the circumcenter?

Your response

Which triple cannot be the sides of a nondegenerate triangle?

Your response

If O lies on the perpendicular bisectors of AB and AC, prove OA=OB=OC and explain why this locates a circle through A,B,C.

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Explain why a triangle's centroid and circumcenter need not coincide. Give an explicit right-triangle example.

Structure your argument and preserve revisions

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Each field allows 2,000 characters. Keep a specific claim, state where it applies, cite the facts you use, and explain what still needs checking. Blank fields are allowed and are not evidence of mastery.

Reflect and continue

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