Place a filled rectangle next to a vertical axis and rotate it through a full turn. Each point traces a circle whose radius is its perpendicular distance from the axis. A horizontal interval of the rectangle therefore sweeps a disk if it reaches the axis, or an annulus if it starts away from it.
The filled generating region matters. Rotating only its far vertical edge produces a cylindrical surface; rotating the entire rectangle fills the interior. Do not use the same word cylinder to hide the distinction between surface and solid when calculating volume.
Predict
Predict the difference between rectangles 0≤x≤3, 0≤z≤5 and 1≤x≤3, 0≤z≤5, each rotated about the z-axis. Their outer profiles match, but one leaves a central hole. Then predict what happens to the first rectangle if the axis changes to the horizontal x-axis. The perpendicular radius and axial length exchange roles.
Experiment
One rectangle, different rotation axes
Rotate the entire filled rectangle through one full turn about the dashed line in its plane. Predict the solid and the area of a section perpendicular to its axis. Rotation takes the union of swept points: overlapping sweeps do not count as extra material.
Generating region: width 4, height 3. Axis: x=0. All lengths use the same unit.
Predict before revealing
Does the axis pass through the region, touch its boundary, or miss it? Identify the nearest and farthest distances from the axis. Decide whether the perpendicular section has a hole.
Try a fresh rectangle and sketch its predicted section before revealing. These controls model ideal filled regions and a full turn; wire outlines and partial turns are different problems. The experiment is temporary and awards no mastery.
The live rectangle settings above are temporary experiments. The fixed diagrams below are separate worked examples; their dimensions do not change with the controls.
Use these equal-scale generating-region drawings. Trace a horizontal segment at z=2 and list all its distances from the axis before imagining the turn. The first range is 0 through 3; the second is 1 through 3.
The first sweep is a radius-3, height-5 cylinder; the second is a tube with inner radius 1, outer radius 3 and height 5. These are generating regions, not perspective pictures of the resulting solids.
Draw the two horizontal section shapes on another sheet at the same scale. Their areas are 9π and 8π square units. Once the cylinder volume rule is justified, the volumes are 45π and 40π cubic units. The removed central tube is real missing volume, not a drawing artifact.
Understand
A triangular generating region produces a cone when one leg lies on the rotation axis. Suppose the vertices in the x,z plane are (0,0),(3,0),(0,6), with rotation about z. Similar triangles give the horizontal radius r(z)=3(1−z/6) for 0≤z≤6. The radius decreases linearly from 3 to zero; the disk area πr(z)² does not decrease linearly. That distinction explains why averaging just the top and bottom areas cannot determine the volume.
A filled right half-disk x≥0, x²+z²≤R² generates a solid ball when rotated about its vertical diameter. At each height, the interval from zero to √(R²−z²) sweeps exactly the sphere section disk. The circular arc alone generates the spherical surface instead. The section rule proves the identification without needing a volume formula first.
Rotation need not preserve a planar region’s area as a useful predictor of volume. For the first rectangle, rotating about x creates radius 5 and axial length 3 rather than radius 3 and length 5. The volumes are therefore different. Also beware of adding overlapping sweeps: either half of a full disk already generates the same ball around a diameter. Adding their swept volumes would double-count the interior.
Apply
For each practice case, name the axis, input region and height coordinate. At a fixed height, give the interval of distances to the axis; this determines whether the section is a disk, an annulus or empty. Sketch a few sections, but use the general distance rule to justify the complete solid.
Volume calculations in this lesson can be revisited after the next formula derivations. The shape identification itself does not depend on accepting the volume formulas from memory.
Axis-change transfer with a retained hole
Use the filled rectangle 0≤x≤2, 1≤y≤3. About the x-axis, every perpendicular section sweeps radii from 1 to 3. The section is an annulus, with area π(3²−1²)=8π. Its axial extent is two units, so the volume is 16π cubic units. The area of the original rectangle is not the rotating section area, and the missing central tube must not be filled in by the sketch.
Rotate the same rectangle about the y-axis instead. Now x measures radial distance and y measures axial position. The radial interval is [0,2], so the section is a filled disk of area 4π; the axial length is 3−1=2. The volume is 8π. The unchanged generating region does not imply unchanged volume because the rotation axis is part of the model.
The experiment replaces the upper y-boundary 3 by R while keeping the other boundaries fixed. Predict each volume before changing R. About x it is 2π(R²−1); about y it is 4π(R−1). At R=1 the region collapses to a line segment and both three-dimensional volumes are zero. This boundary case checks that the formulas reflect the actual region rather than a memorized outer profile.
For each retry, sketch a section perpendicular to the stated axis, label inner and outer radii, and write area times axial length with units. A drawing of the outer surface alone omits the evidence needed to decide whether the solid contains a hole.
Change the axis, rebuild the sections
Review criterion: Use perpendicular distances to the chosen axis and distinguish a filled solid from its boundary.
Predict, then change one input
x-axis section area (square units)
25.132741
x-axis volume (cubic units)
50.265482
y-axis volume (cubic units)
25.132741
Region: 0≤x≤2, 1≤y≤R. About x the sections are annuli; about y they are radius-2 disks with height R−1. Values containing π are displayed approximately.
Explain the changed case: A hole survives
Rotate the filled rectangle 0≤x≤2, 1≤y≤3 about the x-axis. What is the volume?
Axial length: 2
Perpendicular distances from the x-axis: 1 through 3
Write a reason before selecting a claim. Feedback is public practice, not a proof grader.
Inputs and choices are temporary. Nothing is saved, no lesson completion or score is changed, and repeating a public case is not unseen assessment.
Continue
The next lesson explains the circle measures needed for those disk and annulus areas. We will bound circles with polygons and make the approximation error shrink, instead of declaring that a finite many-sided figure is already a circle.
Apply · explain · revise
Practice and reasoning
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Rotate the filled rectangle 0≤x≤3,0≤z≤5 about the z-axis. What is the coefficient of π in its volume in cubic units?
Integers, fractions and finite decimals are accepted. Expressions such as sqrt(2) are not parsed by this checker.
Rotate the rectangle 1≤x≤3,0≤z≤4 about the z-axis. What is the coefficient of π in its volume?
Integers, fractions and finite decimals are accepted. Expressions such as sqrt(2) are not parsed by this checker.
For the rectangle 0≤x≤3,0≤z≤5, compare rotation about the z-axis with rotation about the x-axis. Describe both solids and give the ratio of the second volume to the first.
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Rotate the filled right triangle with vertices (0,0),(4,0),(0,6), using horizontal x and vertical z, about the z-axis. Derive the radius of the horizontal section at height z and identify the solid.
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Rotate the filled right half-disk x≥0,x²+z²≤9 about the z-axis. Compare rotating only its semicircular arc.
Structure your argument and preserve revisions
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Each field allows 2,000 characters. Keep a specific claim, state where it applies, cite the facts you use, and explain what still needs checking. Blank fields are allowed and are not evidence of mastery.
A full disk x²+z²≤4 is rotated about its vertical diameter. A learner adds the swept volumes of its left and right halves. Diagnose the error and give the correct set description.
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Reflect and continue
Before marking this lesson complete, explain one key idea without the worked solution and identify a condition that matters. Marking complete records participation, not independent mastery.