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SCIENCE · INVESTIGATE AND EXPLAIN

Test whether a requested straight crossing is feasible

A velocity stated relative to moving water is not the same as velocity relative to the bank. Add vectors: boat relative to ground equals boat relative to water plus water relative to ground. The supplied virtual channel has width 12 m northward and a uniform current eastward. This is a mathematical exercise only, not swimming, boating or rescue advice.

Learning outcome: Compare current 0,1,2 at relative speed 2, retaining north-aimed drift and straight-across feasibility separately. Predict the equality boundary before checking. Explain which goal remains possible when current exceeds relative speed.

Starting recap

Use SI units, signed components, algebraic ratios and graph coordinates. Identify the measurement rule and distinguish a record from an interpolated model.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

At current3 m/s and relative speed4 m/s, straight-across ground speed is√7 m/s and time ≈4.53557 s. At equal speeds 2 m/s there is no finite straight-across solution, although north-aimed relative motion still reaches the bank downstream.

Open the experiment

Predict

Does relative speed equal to current suffice for a finite directly opposite crossing?

Experiment

Compare current 0,1,2 at relative speed 2, retaining north-aimed drift and straight-across feasibility separately. Predict the equality boundary before checking. Explain which goal remains possible when current exceeds relative speed.

Test a relative-velocity crossing constraint

Worked teaching model · synthetic values · Virtual flat channel width12 m northward, uniform eastward current and fixed relative-water speed. Straight-across ground path requires upstream relative component cancelling current. This is a vector feasibility exercise, not swimming, boating or rescue guidance.

Reset keeps your prediction, captures and practice history.

North-aimed relative-water trajectory in ground frame

north coordinate (m)east coordinate (m)06120

Spatial axes use the same pixels per physical unit, preserving geometry. 1: ground path for north-aimed relative velocity (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for North-aimed relative-water trajectory in ground frame

ground path for north-aimed relative velocity

east coordinate (m)north coordinate (m)
00
612

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Across time when aimed north relative to water6s
East drift when aimed north relative to water6m
Straight-across finite-time solution1flag
Required upstream relative component-1m/s
Northward ground speed1.73205m/s
Straight-across crossing time6.9282s
Heading west of north30degrees

An upstream relative component can cancel current while leaving a positive crossing component.

Aiming north relative to water still reaches the opposite bank downstream for every allowed speed. That differs from reaching the directly opposite point. The straight-across constraint requires water-relative speed greater than current, not merely equal. These supplied vectors are not practical route guidance.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

An upstream relative component can cancel current while leaving a positive crossing component.

Aiming north relative to water still reaches the opposite bank downstream for every allowed speed. That differs from reaching the directly opposite point. The straight-across constraint requires water-relative speed greater than current, not merely equal. These supplied vectors are not practical route guidance.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Begin with a measurement question

A velocity stated relative to moving water is not the same as velocity relative to the bank. Add vectors: boat relative to ground equals boat relative to water plus water relative to ground. The supplied virtual channel has width 12 m northward and a uniform current eastward. This is a mathematical exercise only, not swimming, boating or rescue advice.

Build the algebraic model

If the boat aims north relative to water at speed v, it crosses in 12/v seconds while drifting east by current speed times that time. It reaches the opposite bank but generally not the directly opposite point. Confusing those two goals creates an apparent contradiction between otherwise correct calculations.

Check a concrete implication

To follow a straight northward ground path, the boat must supply a westward relative component equal in magnitude to the eastward current u. Its remaining northward component is √(v²−u²). A finite crossing therefore requires v greater than u. At equality, all available relative speed is directed upstream and the northward component is zero; a zero denominator is not a finite crossing time.

Challenge the evidence boundary

For u=1 m/s and v=2 m/s, north-aimed relative motion takes 6 s and drifts 6 m east. A straight-across ground path instead uses northward speed√3 m/s, takes12/√3≈6.9282 s and points30° west of north relative to the water. The slower direct route follows a different heading constraint, not an error in velocity addition. Real currents, steering and safety are not modeled.

Worked original case

At current3 m/s and relative speed4 m/s, straight-across ground speed is√7 m/s and time ≈4.53557 s. At equal speeds 2 m/s there is no finite straight-across solution, although north-aimed relative motion still reaches the bank downstream.

Predict and investigate

Does relative speed equal to current suffice for a finite directly opposite crossing? Compare current 0,1,2 at relative speed 2, retaining north-aimed drift and straight-across feasibility separately. Predict the equality boundary before checking. Explain which goal remains possible when current exceeds relative speed.

Changed numerical practice

Try the changed case before feedback

For width 12 m,current3 m/s and relative speed5 m/s, find the straight-across crossing time in seconds.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Reflect and source-check

Which velocity belongs in the crossing-time calculation for each heading constraint?

Original explanations, synthetic records and models; checked 30 October 2026 against OpenStax College Physics 2e. The guided calculation is algebra-based; no calculus prerequisite is assumed. All activity is virtual. No physical launch, drop, water crossing, machinery operation or medical decision is requested. A public answer or saved capture does not verify independent mastery or actual measurement technique.

Apply

At current2 m/s and equal relative speed 2 m/s, a directly opposite finite-time crossing is:

Public practice checks a specific claim. It does not establish independent mastery.

Which velocity belongs in the crossing-time calculation for each heading constraint?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

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