Compare route-dependent heat with endpoint-dependent internal energy
Choose the sign convention before balancing thermal energy: heat into the gas is positive and work done by the gas is positive, so ΔU=Q−W. For a quasistatic constant-pressure expansion, W=pΔV; a fixed-volume segment has zero boundary work. On a pressure-volume diagram, the area under the path represents this boundary work.
Learning outcome: Draw both routes and a closed clockwise cycle for two selected endpoints. Keep ΔU, W and Q distinct and explain why equal endpoint temperatures would not generally fix the work or heat.
Starting recap
Declare temperature and time references, system boundaries and model regimes. Use absolute temperatures for ratios; distinguish state, path, oscillator phase and wave propagation.
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For final 150 kPa and 2 L, ΔU=300 J. The high-pressure route does 150 J work and absorbs 450 J heat; the low-pressure route does 100 J work and absorbs 400 J. The clockwise rectangle area is 50 J.
Open the experimentPredict
For two paths between the same equilibrium states of the same ideal gas, the quantity guaranteed equal is:
Experiment
Draw both routes and a closed clockwise cycle for two selected endpoints. Keep ΔU, W and Q distinct and explain why equal endpoint temperatures would not generally fix the work or heat.
Compare heat and work along two paths between the same states
Worked teaching model · synthetic values · Monatomic ideal gas starts at V=1 L and p=100 kPa. Compare heating at fixed initial volume then expansion at final pressure, with expansion at initial pressure then heating at fixed final volume. Quasistatic boundary work and U=3pV/2; no apparatus.
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Two quasistatic routes between shared endpoints
Unlike graph quantities rescale independently; read units and values, not screen angles. 1: raise pressure then expand (solid).2: expand then raise pressure (dashed). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for Two quasistatic routes between shared endpoints
raise pressure then expand
| volume (L) | absolute pressure (kPa) |
|---|---|
| 1 | 100 |
| 1 | 200 |
| 3 | 200 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
expand then raise pressure
| volume (L) | absolute pressure (kPa) |
|---|---|
| 1 | 100 |
| 3 | 100 |
| 3 | 200 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Endpoint internal-energy change | 750 | J |
| Work by gas on high-pressure expansion path | 400 | J |
| Work by gas on low-pressure expansion path | 200 | J |
| Heat into gas on high-pressure path | 1150 | J |
| Heat into gas on low-pressure path | 950 | J |
| Clockwise rectangle cycle work | 200 | J |
Internal energy depends on endpoints; heat and boundary work depend on the route.
One kPa litre equals one joule. With work by the gas positive, Delta U=Q−W. Isochoric segments do no boundary work, while a constant-pressure expansion does p Delta V. A clockwise closed rectangle does positive net work but has zero net Delta U. Isothermal ideal-gas change has Delta U=0, not necessarily Q=0; adiabatic means Q=0, not necessarily constant temperature.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
Internal energy depends on endpoints; heat and boundary work depend on the route.
One kPa litre equals one joule. With work by the gas positive, Delta U=Q−W. Isochoric segments do no boundary work, while a constant-pressure expansion does p Delta V. A clockwise closed rectangle does positive net work but has zero net Delta U. Isothermal ideal-gas change has Delta U=0, not necessarily Q=0; adiabatic means Q=0, not necessarily constant temperature.
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