Use center distance in gravity and orbital comparisons
For an ideal spherical source, exterior gravitational force has magnitude GMm/r², where r is center-to-center separation. Altitude above the surface is h=r−R, not r. Substituting altitude into the denominator would predict a singular field at the surface even though the source-center distance remains finite.
Learning outcome: Compare radii R,2R,3R at one test mass; retain field, force, speed and period ratios. Then change mass alone. Explain why equal periods need not imply equal instantaneous speeds at every point of a noncircular orbit.
Starting recap
Draw recipient-specific interactions, resolve signed components and identify the domain of each force/contact model before substituting.
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At r=2R=1.2×10^7 m, g≈2.77778 m/s² and circular speed≈5773.50 m/s. A 2 kg test mass feels≈5.55556 N. Compared with r=R, speed is divided by√2 and period multiplied by 2√2.
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At altitude equal to one source radius, exterior gravity is:
Experiment
Compare radii R,2R,3R at one test mass; retain field, force, speed and period ratios. Then change mass alone. Explain why equal periods need not imply equal instantaneous speeds at every point of a noncircular orbit.
Distinguish orbital radius from altitude
Worked teaching model · synthetic values · Ideal spherical source has GM=4e14 m³/s² and radius 6e6 m. Exterior gravity only, negligible test mass, no atmosphere or other sources. Surface-radius circular motion is a mathematical limit, not an accessible flight path.
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Exterior gravity versus center distance
Unlike graph quantities rescale independently; read units and values, not screen angles. 1: inverse-square field (solid). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for Exterior gravity versus center distance
inverse-square field
| radius in planet radii | gravitational acceleration (m/s²) |
|---|---|
| 1 | 11.1111 |
| 1.05 | 10.0781 |
| 1.1 | 9.18274 |
| 1.15 | 8.4016 |
| 1.2 | 7.71605 |
| 1.25 | 7.11111 |
| 1.3 | 6.57462 |
| 1.35 | 6.09663 |
| 1.4 | 5.66893 |
| 1.45 | 5.28471 |
| 1.5 | 4.93827 |
| 1.55 | 4.62481 |
| 1.6 | 4.34028 |
| 1.65 | 4.08122 |
| 1.7 | 3.84468 |
| 1.75 | 3.62812 |
| 1.8 | 3.42936 |
| 1.85 | 3.24649 |
| 1.9 | 3.07787 |
| 1.95 | 2.92205 |
| 2 | 2.77778 |
| 2.05 | 2.64393 |
| 2.1 | 2.51953 |
| 2.15 | 2.4037 |
| 2.2 | 2.29568 |
| 2.25 | 2.19479 |
| 2.3 | 2.1004 |
| 2.35 | 2.01197 |
| 2.4 | 1.92901 |
| 2.45 | 1.85108 |
| 2.5 | 1.77778 |
| 2.55 | 1.70874 |
| 2.6 | 1.64366 |
| 2.65 | 1.58222 |
| 2.7 | 1.52416 |
| 2.75 | 1.46924 |
| 2.8 | 1.41723 |
| 2.85 | 1.36794 |
| 2.9 | 1.32118 |
| 2.95 | 1.27677 |
| 3 | 1.23457 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Center-to-center orbital radius | 12000000 | m |
| Altitude above ideal surface | 6000000 | m |
| Gravitational acceleration magnitude | 2.77778 | m/s² |
| Gravitational force magnitude | 5.55556 | N |
| Ideal circular orbital speed | 5773.5 | m/s |
| Ideal circular period | 13059.4 | s |
| Period squared over radius cubed | 9.8696e-14 | s²/m³ |
Orbital free fall needs gravity; doubling test mass doubles force but not gravitational acceleration.
F=GMm/r² and mv²/r give v²=GM/r for a circular test-particle orbit. Combining T=2pi r/v gives T²/r³=4pi²/(GM). Use radius from the source center, not altitude. Elliptical orbits have changing speed and are not generated by this circular comparison; equal-area and common-source period relations need the stated ideal two-body assumptions.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
Orbital free fall needs gravity; doubling test mass doubles force but not gravitational acceleration.
F=GMm/r² and mv²/r give v²=GM/r for a circular test-particle orbit. Combining T=2pi r/v gives T²/r³=4pi²/(GM). Use radius from the source center, not altitude. Elliptical orbits have changing speed and are not generated by this circular comparison; equal-area and common-source period relations need the stated ideal two-body assumptions.
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Public practice checks a specific claim. It does not establish independent mastery.
Why must common-source and small-test-mass assumptions accompany the period comparison?
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