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SCIENCE · INVESTIGATE AND EXPLAIN

Use center distance in gravity and orbital comparisons

For an ideal spherical source, exterior gravitational force has magnitude GMm/r², where r is center-to-center separation. Altitude above the surface is h=r−R, not r. Substituting altitude into the denominator would predict a singular field at the surface even though the source-center distance remains finite.

Learning outcome: Compare radii R,2R,3R at one test mass; retain field, force, speed and period ratios. Then change mass alone. Explain why equal periods need not imply equal instantaneous speeds at every point of a noncircular orbit.

Starting recap

Draw recipient-specific interactions, resolve signed components and identify the domain of each force/contact model before substituting.

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Try

At r=2R=1.2×10^7 m, g≈2.77778 m/s² and circular speed≈5773.50 m/s. A 2 kg test mass feels≈5.55556 N. Compared with r=R, speed is divided by√2 and period multiplied by 2√2.

Open the experiment

Predict

At altitude equal to one source radius, exterior gravity is:

Experiment

Compare radii R,2R,3R at one test mass; retain field, force, speed and period ratios. Then change mass alone. Explain why equal periods need not imply equal instantaneous speeds at every point of a noncircular orbit.

Distinguish orbital radius from altitude

Worked teaching model · synthetic values · Ideal spherical source has GM=4e14 m³/s² and radius 6e6 m. Exterior gravity only, negligible test mass, no atmosphere or other sources. Surface-radius circular motion is a mathematical limit, not an accessible flight path.

Reset keeps your prediction, captures and practice history.

Exterior gravity versus center distance

gravitational acceleration (m/s²)radius in planet radii0311.11110

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: inverse-square field (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Exterior gravity versus center distance

inverse-square field

radius in planet radiigravitational acceleration (m/s²)
111.1111
1.0510.0781
1.19.18274
1.158.4016
1.27.71605
1.257.11111
1.36.57462
1.356.09663
1.45.66893
1.455.28471
1.54.93827
1.554.62481
1.64.34028
1.654.08122
1.73.84468
1.753.62812
1.83.42936
1.853.24649
1.93.07787
1.952.92205
22.77778
2.052.64393
2.12.51953
2.152.4037
2.22.29568
2.252.19479
2.32.1004
2.352.01197
2.41.92901
2.451.85108
2.51.77778
2.551.70874
2.61.64366
2.651.58222
2.71.52416
2.751.46924
2.81.41723
2.851.36794
2.91.32118
2.951.27677
31.23457

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Center-to-center orbital radius12000000m
Altitude above ideal surface6000000m
Gravitational acceleration magnitude2.77778m/s²
Gravitational force magnitude5.55556N
Ideal circular orbital speed5773.5m/s
Ideal circular period13059.4s
Period squared over radius cubed9.8696e-14s²/m³

Orbital free fall needs gravity; doubling test mass doubles force but not gravitational acceleration.

F=GMm/r² and mv²/r give v²=GM/r for a circular test-particle orbit. Combining T=2pi r/v gives T²/r³=4pi²/(GM). Use radius from the source center, not altitude. Elliptical orbits have changing speed and are not generated by this circular comparison; equal-area and common-source period relations need the stated ideal two-body assumptions.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Orbital free fall needs gravity; doubling test mass doubles force but not gravitational acceleration.

F=GMm/r² and mv²/r give v²=GM/r for a circular test-particle orbit. Combining T=2pi r/v gives T²/r³=4pi²/(GM). Use radius from the source center, not altitude. Elliptical orbits have changing speed and are not generated by this circular comparison; equal-area and common-source period relations need the stated ideal two-body assumptions.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define the recipient and model

For an ideal spherical source, exterior gravitational force has magnitude GMm/r², where r is center-to-center separation. Altitude above the surface is h=r−R, not r. Substituting altitude into the denominator would predict a singular field at the surface even though the source-center distance remains finite.

Build the algebraic relationship

The synthetic source has GM=4×10^14 m³/s² and radius R=6×10^6 m. At center distance2R, gravity is one quarter of its surface value. Doubling the small test mass doubles gravitational force but leaves acceleration GM/r² unchanged. This comparison assumes the source is overwhelmingly more massive and its motion and other bodies can be neglected.

Check the changed state

For a circular orbit, gravity supplies mv²/r, so v=√(GM/r). Combining this with period T=2πr/v gives T²/r³=4π²/(GM). A larger circular orbit has smaller speed but longer period. An orbiting point is continuously falling under gravity; an absent support force does not imply that gravity has become negligible.

Interpret evidence and limits

General bound two-body orbits are ellipses with the source at one focus, with equal areas swept in equal times; the circular case is a special ellipse with constant speed. For common-source elliptical comparisons, the period relation uses semimajor axis, not arbitrary instantaneous radius. This workbench calculates circular states only. At r=R it shows an ideal mathematical limit, not a physically accessible orbit through atmosphere or surface terrain.

Worked original packet

At r=2R=1.2×10^7 m, g≈2.77778 m/s² and circular speed≈5773.50 m/s. A 2 kg test mass feels≈5.55556 N. Compared with r=R, speed is divided by√2 and period multiplied by 2√2.

Bounded investigation

Compare radii R,2R,3R at one test mass; retain field, force, speed and period ratios. Then change mass alone. Explain why equal periods need not imply equal instantaneous speeds at every point of a noncircular orbit.

Changed-case numerical practice

Try the changed case before feedback

Two ideal circular orbits around the same dominant source have radii r and 4r. What is the ratio of the larger orbit’s period to the smaller orbit’s period?

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original prose, data and diagrams checked 30 October 2026 against OpenStax College Physics 2e. This is an algebra-based virtual evidence exercise, not a physical experiment, equipment certification, transport recommendation or independent mastery result. Save assumptions and a competing explanation with the course evidence; supervised practical requirements remain external.

Apply

At altitude equal to one source radius, exterior gravity is:

Public practice checks a specific claim. It does not establish independent mastery.

Why must common-source and small-test-mass assumptions accompany the period comparison?

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