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SCIENCE · INVESTIGATE AND EXPLAIN

Calculate photon energy without confusing it with power

Convert wavelength to frequency and photon energy, then calculate photon rate from beam power.

Learning outcome: Convert wavelength to frequency and photon energy, then calculate photon rate from beam power.

Starting recap

Vacuum light satisfies c=fλ; power is joules per second. An electron volt is an energy unit, not a voltage.

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Try

Compare a 500 nm beam at 2 mW with the same wavelength at 4 mW.

Open the experiment

Predict

Does a brighter beam have more energetic individual photons?

Experiment

Capture 500 nm at 2 and 4 mW. Then keep power 2 mW and change to 250 nm. Compare photon energies and rates independently.

Separate photon energy from beam power

Worked teaching model · synthetic values · Monochromatic ideal beam; exact SI h,c,e. Beam power is energy per second, not energy per photon. No eye exposure or real apparatus is proposed.

Reset keeps your prediction, captures and practice history.

QuantityCalculated valueUnit
Photon energy2.4797eV per photon

Each photon carries 2.4797 eV.

Frequency 5.9958e+14 Hz; energy 3.9729e-19 J; photon rate 5.0341e+15 s⁻¹. Doubling power doubles rate, not photon energy.

Model boundary: Monochromatic ideal beam; exact SI h,c,e. Beam power is energy per second, not energy per photon. No eye exposure or real apparatus is proposed.

All investigations are virtual. Do not obtain radioactive sources, expose eyes to bright beams, or build high-voltage apparatus. Notebook captures preserve selected recipes, not physical measurements.

Each photon carries 2.4797 eV.

Frequency 5.9958e+14 Hz; energy 3.9729e-19 J; photon rate 5.0341e+15 s⁻¹. Doubling power doubles rate, not photon energy.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Two quantities that a bright lamp can hide

A beam supplies energy over time; a photon carries an individual quantum of that energy. We can hold one quantity fixed while changing the other. In this original comparison, the wavelength is 500 nm and beam power is 2 mW. Neither value describes a real device or gives permission to illuminate an eye.

Convert 500 nm to 5×10⁻⁷ m. Frequency is c/λ≈5.996×10¹⁴ Hz. Multiplying by Planck’s constant gives E≈3.973×10⁻¹⁹ J per photon. Dividing by 1.602176634×10⁻¹⁹ J/eV gives about 2.480 eV. The unit conversion changes the numerical representation, not the energy.

Reconstruct the photon rate

Two milliwatts is 0.002 J/s. Divide this by energy per photon to obtain approximately 5.034×10¹⁵ photons/s. A larger number of photons is not a larger energy for each photon. Capture the result before changing a control, and write your predicted ratio for the next run.

At 4 mW with the same 500 nm wavelength, energy per photon stays 2.480 eV while photon rate doubles. At 250 nm and 2 mW, each photon has twice the original energy, so only half as many photons per second supply the same power. These relations depend on a monochromatic beam. A source with a distribution of wavelengths needs an energy-weighted calculation rather than one arbitrary wavelength.

Check a new beam

A 750 nm beam supplies 3 mW. Calculate energy per photon, photon rate and the ratio of photon rates compared with 500 nm at 2 mW. Show metres and watts before substituting.

Worked transfer

Energy≈2.649×10⁻¹⁹ J≈1.653 eV. Rate≈1.133×10¹⁶ s⁻¹. The ratio is(3/2)×(750/500)=2.25. The 750 nm photon has less energy even though this beam has greater power and a greater photon rate.

Where the explanation applies

The model omits bandwidth, detector efficiency, reflection and absorption. It cannot infer tissue damage, detector counts or electrical output from beam power alone. Classical wave intensity remains useful for describing a beam’s average energy flow; the photon account is needed when an interaction transfers discrete energy. One representation does not make the other universally wrong.

Source and authorship

Reference for the physical relationship. Source checked 30 October 2026. The explanations, numerical cases, questions and diagrams here are original; reference material is not copied. Exact h,c,e follow NIST SI definitions.

Apply

At fixed wavelength, doubling beam power doubles:

Public practice checks a specific claim. It does not establish independent mastery.

Explain why doubling power and halving wavelength affect different quantities. Show unit conversions and state the monochromatic assumption.

Continue

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