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SCIENCE · INVESTIGATE AND EXPLAIN

Connect current, voltage and resistance

Use charge flow and a voltage sweep to interpret an ohmic circuit.

Learning outcome: Calculate current and transported charge, distinguish current from voltage, and interpret current-versus-voltage slope.

Starting recap

A volt is a joule per coulomb; an ampere is a coulomb per second. Milliamperes must be divided by 1000 before multiplying seconds.

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Try

Does a resistor consume charge, or transfer energy?

Open the experiment

Predict

At R2 = 200 Ω, predict source currents at 6 V and 12 V in each circuit.

Experiment

Capture 6 V and 12 V with resistance fixed. Use the sweep to compare slopes; inspect 0 V without calling it an open circuit.

Compare series and parallel resistor circuits

Worked teaching model · synthetic values · Two separate steady DC circuits compared at the same ideal source voltage. R1 = 100 Ω; R2 = 100–500 Ω. Constant ohmic resistance, zero-resistance wires and no source internal resistance. No switching transient, capacitance, inductance, heating feedback, component failure or meter loading. Drawn arrows indicate conventional current reference directions, not electron trajectories or speed. Energy and charge totals assume the displayed current remains constant for 60 s. Values are synthetic predictions, not measurements or physical component ratings. Zero source voltage is a connected zero-voltage case, not an open circuit.

Reset keeps your prediction, captures and practice history.

Series: one path

Separate ideal 6 V source · conventional current reference arrows+−6 VR1 = 100 ΩDrop 2.000 V20.000 mAR2 = 200 ΩDrop 4.000 V20.000 mASame current through both resistorsReturn current 20.000 mA · no charge consumedSteady state; wires and source internal resistance idealized.
series resistor values and energy
ComponentResistance (Ω)Current (mA)Drop (V)Power (W)Energy in 60 s (J)
R110020.0002.0000.0402.400
R220020.0004.0000.0804.800

Equivalent resistance 300.000 Ω; source current 20.000 mA; source power 0.120 W. Over 60 s: source energy 7.200 J and charge through the source 1.200 C. Resistor powers sum to 0.120 W.

Parallel: two branches

Separate ideal 6 V source · conventional current reference arrows+−6 VR1 = 100 Ω6.000 V · 60.000 mAR2 = 200 Ω6.000 V · 30.000 mAReturn current 90.000 mA · no charge consumedSteady state; wires and source internal resistance idealized.
parallel resistor values and energy
ComponentResistance (Ω)Current (mA)Drop (V)Power (W)Energy in 60 s (J)
R110060.0006.0000.36021.600
R220030.0006.0000.18010.800

Equivalent resistance 66.667 Ω; source current 90.000 mA; source power 0.540 W. Over 60 s: source energy 32.400 J and charge through the source 5.400 C. Resistor powers sum to 0.540 W.

Source current versus voltage · same R1 and R2 · mA060120180240024681012Source voltage (V) · solid: series · dashed: parallel
Source currents at fixed resistance
Source voltage (V)Series current (mA)Parallel current (mA)
00.0000.000
26.66730.000
413.33360.000
620.00090.000
826.667120.000
1033.333150.000
1240.000180.000

Series source current 20.000 mA; parallel source current 90.000 mA.

Equivalent resistances 300.000 Ω and 66.667 Ω. Source powers 0.120 W and 0.540 W; energy delivered in 60 s 7.200 J and 32.400 J. Each circuit has its own source.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

From a stationary charge to a steady flow

A circuit can transfer energy continuously while its charge distribution remains approximately steady. Current is the rate at which net charge passes a cross-section: I = ΔQ/Δt, where I is current in amperes (A), ΔQ is charge in coulombs (C), and Δt is elapsed time in seconds (s). One ampere is one coulomb per second; 1 mA = 0.001 A. Conventional current follows the direction positive charge would move. In a metal, electron drift is opposite that direction.

Voltage is different: it measures energy change per charge between two points. Resistance relates a component’s voltage drop to its current. For an ohmic resistor under fixed conditions, V = IR, where resistance R is measured in ohms (Ω). This proportional relationship is a model for suitable components, not a promise that every device has constant resistance.

Try both circuits at the same voltage

The browser supplies two separate sources and the same resistor values in two connections. At the default 6 V, the series source delivers 20 mA, while the parallel source delivers 90 mA. The different currents do not contradict the common voltage: the connections present different equivalent resistances, 300 Ω and 66.667 Ω respectively.

Before changing voltage to 12 V, write the expected currents. Capture both settings with R2 held at 200 Ω. The model gives 40 mA and 180 mA, twice the corresponding initial currents. The larger current is not faster motion of the drawn arrow; arrows indicate reference direction only.

At 20 mA held for 60 s, charge passing through the series source is (0.020 A)(60 s) = 1.2 C. At 90 mA it is 5.4 C. This counts transported charge, not charge created by the source or consumed by a resistor. The model has no particle-tracking animation and does not calculate electron drift speed.

Read the slope with its axes

The graph has current on the vertical axis and voltage on the horizontal axis. Its slope is I/V = 1/R equivalent, called conductance. A steeper line indicates smaller equivalent resistance. On a graph with voltage vertical and current horizontal, the slope would instead be resistance. Always identify axes and units before interpreting a slope.

At 0 V both model currents are zero, but the connected resistor networks still have their defined equivalent resistances. The ratio 0/0 cannot measure resistance from that one point; use nonzero readings or the slope. Zero source voltage is not the same circuit condition as a broken wire.

Transfer beyond the sliders

A steady 15 mA current passes a point for 40 s. How much charge passes? Separately, an ohmic component has 3 V across it and carries 15 mA. Infer its resistance and predict current at 4.5 V if its resistance stays constant.

Check the current transfer

Charge = 0.015 × 40 = 0.60 C. Resistance = 3/0.015 = 200 Ω. At 4.5 V, current = 4.5/200 = 0.0225 A = 22.5 mA. The last prediction depends on unchanged resistance; a heated filament or diode may not obey it.

OpenStax: electrical current explains charge flow and direction. Ohm’s law discusses the proportional model and its limits. The browser values above are original synthetic comparisons, not measurements.

Apply

Doubling source voltage with fixed ohmic resistances makes the source current:

Public practice checks a specific claim. It does not establish independent mastery.

Explain charge flow, voltage difference and the conditions for constant resistance.

Continue

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