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SCIENCE · INVESTIGATE AND EXPLAIN

Interpret saturation limits without hiding the result

Retain a supersaturated proposal and distinguish state arithmetic from condensation physics.

Learning outcome: Diagnose RH above 100% and state what extra processes and observations are needed to predict condensation.

Starting recap

RH above 100% means supplied vapor pressure exceeds the liquid-water saturation value. The browser retains that calculation and flags the proposed state.

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Try

At 10°C with e = 20 hPa, raw RH is about 163%, placing the proposal outside the model’s non-supersaturated equilibrium interpretation.

Open the experiment

Predict

Would silently clamping a raw relative humidity above 100% preserve the supplied vapor-pressure relationship?

Experiment

At vapor pressure 20 hPa compare 20, 18, 16 and 10°C. Capture a non-supersaturated case and a flagged proposal, preserving the raw values.

Separate humidity, temperature and dew point

Worked teaching model · synthetic values · Liquid-water saturation approximation over 0–40 °C; fixed total pressure 1000 hPa. Changing temperature at fixed vapor partial pressure preserves the vapor-to-dry-air mass ratio before saturation, not the volume of a sealed container. Supersaturated proposals remain visible; no condensation, latent heat, nuclei, ice, cloud evolution or precipitation is calculated. Synthetic settings are not weather observations.

Reset keeps your prediction, captures and practice history.

Temperature and vapor pressure · liquid-water approximationCircle: proposed state · square: saturation at selected temperature020406080hPa010203040Temperature (°C) · dashed intersection: dew point 17.51 °CCurve: saturation pressure · horizontal dashed line: supplied vapor pressure
Temperature, vapor abundance and saturation are different quantities
QuantityValue and interpretation
Air temperature T20 °C
Vapor partial pressure e20 hPa
Saturation pressure eₛ(T)23.369 hPa, equilibrium over liquid water
Relative humidity 100e/eₛ85.58%, retained even above 100%
Dew point Tᵈ17.51 °C, where eₛ(Tᵈ) = e
Mixing ratio 622e/(1000 − e)12.694 g vapor/kg dry air
Temperature minus dew point2.49 °C; negative means the proposed vapor pressure exceeds saturation

At or below saturation. Cooling at fixed vapor pressure reaches saturation at the dew point. Continued cooling with condensation would change the vapor pressure; the controls do not calculate that process.

Warm the air at fixed vapor pressure: relative humidity falls while dew point and mixing ratio stay fixed. Add vapor at fixed temperature: all three rise. Neither comparison alone predicts rain or cloud cover. The formula is approximate, refers to liquid water, and is not an ice frost-point calculation.

Relative humidity 85.58%; dew point 17.51 °C. At or below liquid-water saturation.

eₛ = 6.112 exp(17.67T/(T + 243.5)) hPa; RH = 100e/eₛ. Vapor mixing ratio = 12.694 g/kg dry air at 1000 hPa total pressure. Raw relative humidity is not clamped to 100%.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Keep the raw calculation visible

At air temperature 10°C and supplied vapor pressure 20 hPa, saturation pressure over liquid water is about 12.27 hPa. The calculated ratio is therefore approximately 163%. The browser retains that value and marks the proposed state as supersaturated. It does not silently replace the answer with 100%.

Supersaturation means vapor pressure exceeds the selected equilibrium saturation value. It is not a mathematical failure of the positive-pressure ratio. Transient supersaturation can occur in physical systems, but the browser does not model its lifetime or how it relaxes through condensation. The proposal is outside the non-supersaturated equilibrium interpretation used for the basic state comparison.

Diagnose the proposed state step by step

Hold vapor pressure at 20 hPa. Capture temperatures 20, 18, 16 and 10°C. The dew point stays near 17.51°C. The first two temperatures lie above that threshold; the latter two lie below and produce raw RH above 100%.

For every capture, record supplied e, calculated e_s and their ratio. State whether the air-temperature marker is above or below the calculated dew point. These are linked checks of one state relation. Agreement between them is useful for detecting arithmetic errors, but it is not several independent pieces of observational evidence.

If the display were clamped to 100% while the inputs remained unchanged, the equation RH = 100e/e_s would no longer explain the shown number. Clamping would conceal how far the proposal exceeds the threshold. A physically updated equilibrium state would require changing vapor amount or other conditions through a specified process, not merely changing the displayed percentage.

Distinguish a threshold from a condensation amount

The difference e − e_s is a pressure difference. It is not directly a mass of liquid water. Calculating a condensed amount would require a defined parcel or control volume, mass accounting and a process model. Temperature can also change when latent heat is released, and the current browser does not solve that coupled problem.

The controls supply a state, not a cooling experiment. Total pressure is fixed at 1000 hPa, and fixed e implies fixed mixing ratio before the saturation limit is crossed. They do not describe a sealed, fixed-volume vessel whose partial pressures automatically evolve with temperature. The user-selected values remain proposals even when they are incompatible with the simpler equilibrium interpretation.

On paper draw a boundary around a hypothetical parcel and list the additional terms a condensation model would need. Include vapor and liquid masses, heat exchange and the constraints on pressure or volume. Leave the quantities unknown rather than inventing a rainfall result from RH alone.

Ask which observations address the claim

A claim about dew on a surface needs information about that surface and surrounding air. A claim about fog requires more than a bulk RH calculation. A claim about precipitation needs cloud and transport processes absent here. A single saturated state does not determine duration, droplet sizes, rain rate or the location of condensation.

Design an observation ledger for one such question. Separate direct readings, sensor uncertainty, calculated dew point and the process inference. If two sensors disagree, retain both readings and investigate calibration, placement and timing instead of forcing a preferred humidity value.

The numerical relation is an approximation over liquid water. Its phase convention matters: this lesson does not replace it with an ice formula or claim to predict frost. The NWS formula reference supplies the saturation, ratio and inverse relations used here; the browser’s diagnostic interpretation remains explicitly bounded. NWS calculation reference.

Report a useful limitation

A defensible conclusion can say that the supplied values produce a supersaturated proposal and name the missing physics. It should not say that supersaturation is universally impossible, that the calculation measured condensation, or that the number predicts tomorrow’s weather.

Save a non-supersaturated case beside a flagged case and explain which input change crossed the threshold. This comparison preserves both the valid arithmetic and the limits of the physical interpretation.

Transfer: audit a clamped display

A proposed state has e = 15 hPa and e_s = 10 hPa. A dashboard reports 100% RH without changing either pressure. What should its raw ratio be, and what does the correction establish?

Check the saturation-evidence transfer

The raw ratio is 100 × 15/10 = 150%. Reporting it with a supersaturation flag preserves the supplied state relation. This identifies a proposal above liquid-water saturation; it does not calculate how much condenses, how rapidly it occurs or whether precipitation reaches the ground.

Apply

The supplied inputs produce raw RH above 100%. The appropriate interpretation is:

Public practice checks a specific claim. It does not establish independent mastery.

Separate supersaturation from a condensation forecast, explain why clamping hides a mismatch, and list information absent from a fog or rain prediction.

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

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