Estimate a lifting condensation level
Find where simplified parcel temperature and dew-point paths meet, then apply a separate saturated cooling rule.
Learning outcome: Derive the approximate LCL and retain continuity across the change in cooling rate.
Starting recap
The LCL is the saturation height of a hypothetically lifted parcel. Here its pre-saturation temperature falls 9.8°C/km and dew point falls an assumed 1.8°C/km.
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Try
An initial 8°C separation closes at 8°C/km, giving an approximate LCL of 1 km and parcel temperature 20.2°C there.
Open the experimentPredict
If the initial temperature–dew-point separation doubles, how does this model’s LCL change?
Experiment
Compare surface differences 0, 8 and 16°C. Compute each LCL, check the parcel temperature there and explain the slope change above it.
Lift a parcel through a temperature profile
Worked teaching model · synthetic values · Synthetic parcel and environment both start at 30 °C. Prescribed cooling: unsaturated parcel 9.8 °C/km, its dew point approximately 1.8 °C/km, saturated parcel a fixed teaching approximation of 6 °C/km. Actual moist cooling varies with pressure and temperature. Height spans 0–3 km above the starting level. No mixing, virtual-temperature correction, condensate loading, pressure solver, lift force, time evolution or precipitation. Temperature differences are only a buoyancy proxy, not CAPE or an actual forecast.
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Conditionally unstable lapse-rate comparison. This compares assumed lapse rates, not the weather outcome. The post-saturation parcel/environment temperature equality is 3.80 km (beyond this 3 km plot). The temperature equality is not a virtual-temperature-corrected level of free convection.
| Height above start | Parcel | Environment | Parcel minus environment | Parcel stage |
|---|---|---|---|---|
| 0.00 km | 30.00 °C | 30.00 °C | 0.00 °C | Unsaturated approximation |
| 0.50 km | 25.10 °C | 26.50 °C | -1.40 °C | Unsaturated approximation |
| 1.00 km · condensation level | 20.20 °C | 23.00 °C | -2.80 °C | Saturated approximation |
| 1.50 km | 17.20 °C | 19.50 °C | -2.30 °C | Saturated approximation |
| 2.00 km | 14.20 °C | 16.00 °C | -1.80 °C | Saturated approximation |
| 2.50 km | 11.20 °C | 12.50 °C | -1.30 °C | Saturated approximation |
| 3.00 km | 8.20 °C | 9.00 °C | -0.80 °C | Saturated approximation |
Positive temperature difference means warmer, negative means colder. At equal pressure and comparable composition this suggests a buoyancy tendency; actual density also depends on moisture and suspended condensate. This model supplies neither vertical speed nor the force needed to lift a colder parcel.
The initial gap is 8 °C. Its approximate closing rate is 9.8 − 1.8 = 8 °C/km, giving 1.00 km (1000 m). Rising air expands as surrounding pressure falls. Unlike the preceding humidity state comparison, pressure is not held fixed along this conceptual ascent. Cloud formation and precipitation require additional microphysics and observations.
Approximate lifting condensation level 1.00 km. At 3 km parcel minus environment = -0.80 °C.
Conditionally unstable lapse-rate comparison. Condensation level comes from the closing temperature–dew-point gap: 8/(9.8 − 1.8) km. Saturation does not guarantee that the parcel is warmer than its environment or that rain develops.
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Show the gap-closing calculation, name the fixed-rate assumptions and explain why this LCL does not guarantee a cloud or rain event.
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