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SCIENCE · INVESTIGATE AND EXPLAIN

Connect energy imbalance to temperature change

Use heat capacity to distinguish energy flux, stored energy and a temperature-change rate.

Learning outcome: Calculate initial warming and stored-energy anomalies for a synthetic effective reservoir.

Starting recap

A watt is a joule per second; heat capacity specifies joules per area needed for a kelvin of change.

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Try

At depth 50 m, capacity is 205 million J m⁻² K⁻¹ and the initial 4 W/m² input gives about 0.61576 K/year.

Open the experiment

Predict

Does doubling effective reservoir depth change the initial warming rate under the same forcing?

Experiment

Compare depths 50 and 100 m at fixed feedback. Reconstruct initial rate and ledger net flux, then calculate stored energy from temperature.

Store energy and trace a feedback response

Worked teaching model · synthetic values · Synthetic uniform linear reservoir: C = 4.1 million × depth J/m²/K, baseline damping 3.2 W/m²/K. An imposed +4 W/m² forcing acts until year 25, then is removed. Temperature starts at zero anomaly. Positive feedback f adds fθ to net input; total damping 3.2 − f stays positive. Exact piecewise solutions, not time-stepped estimates. Effective depth and coefficients are teaching assumptions, not fitted climate parameters or measured ocean properties.

Reset keeps your prediction, captures and practice history.

Change one parameter and compare the solid selected response with the dashed no-added-feedback reference (f = 0) at the same reservoir depth. The full forcing pulse and recovery are shown without animation. A year is 31,557,600 seconds in this model. Values displayed as zero may be rounded small values.

Storage, damping and the target if forcing were maintained
QuantitySelected responseNo-added-feedback reference
Areal heat capacity (MJ/m²/K)205.000205.000
Total damping (W/m²/K)2.0003.200
Response time (years)3.2482.030
Initial warming rate (K/year)0.6160.616
Target if +4 W/m² persisted (K)2.0001.250
Actual peak at removal, year 25 (K)1.9991.250
Temperature anomaly (K) · solid selected / dashed f = 0 reference+4 W/m² for years 0–25; zero thereafter · removal at the dotted line00.511.522.533.50255075100Elapsed model years · synthetic trajectories, not historical observations
Net energy input (W/m²) · solid selected / dashed f = 0 reference+4 W/m² for years 0–25; zero thereafter · removal at the dotted line-4-20240255075100Elapsed model years · synthetic trajectories, not historical observations
Stored energy anomaly (MJ/m²) · solid selected / dashed f = 0 reference+4 W/m² for years 0–25; zero thereafter · removal at the dotted line05001000150020000255075100Elapsed model years · synthetic trajectories, not historical observations

At the vertical removal line, temperature and stored energy are continuous. Net input drops by exactly 4 W/m²; the vertical segment is a prescribed jump, not a numerical overshoot. A positive temperature anomaly can coexist with negative net input while stored energy is being lost. The finite pulse does not have to reach the sustained-forcing target before it ends.

Signed fluxes and storage at selected times, including both sides of removal
Model yearθ (K)Forcing F (W/m²)Baseline −3.2θ (W/m²)Feedback fθ (W/m²)Net N (W/m²)Storage E (MJ/m²)
00.0004.0000.0000.0004.0000.000
51.5714.000-5.0271.8850.858322.051
101.9084.000-6.1062.2900.184391.134
25 just before1.9994.000-6.3972.3990.002409.814
25 just after1.9990.000-6.3972.399-3.998409.814
500.0010.000-0.0030.001-0.0020.186
1000.0000.0000.0000.0000.0000.000

The feedback loop is explicit: temperature anomaly θ changes the flux fθ; that flux changes net energy input N; N changes stored energy and therefore θ. Here positive f reinforces the imposed warming and negative f opposes it. The baseline response −3.2θ is always restoring. Total damping λ = 3.2 − f remains positive across every control setting, so positive added feedback does not mean runaway growth.

Energy accounting is C dθ/dt = N = F − 3.2θ + fθ and E = Cθ. C is heat capacity per area, θ is temperature change in kelvin, F and N are power per area, and t is time in seconds. The derivative means rate of temperature change. For constant forcing, target temperature is F/λ and response time is τ = C/λ. The warming solution is θ = (4/λ)[1 − exp(−t/τ)]; after removal it is θ = θ₂₅ exp[−(t − t₂₅)/τ], with all times in consistent units. The exponential gives the fraction of the remaining adjustment. The graphs sample these exact solutions; graph spacing is not an integration step.

The reference has no added feedback, but retains baseline radiative damping. Depth is an effective water-equivalent storage parameter, not actual ocean depth or a measured mixed layer. The prescribed linear response resolves no cloud, ice, water-vapor or circulation process. There are no multiple reservoirs, geography, seasonal variation, noise or gas-concentration mapping. Removing this imposed forcing is not equivalent to stopping CO₂ emissions. The 4 W/m² pulse and coefficient choices are teaching assumptions, not an estimate of real-world equilibrium climate sensitivity.

NASA's energy-budget explanation provides context for storage and delayed temperature response. IPCC AR6 Chapter 7 discusses forcing and radiative feedbacks; its net-feedback sign convention differs from the positive-damping λ used here.

Response time 3.248 years; sustained-forcing target 2.000 K. At year 25 the anomaly is 1.999 K.

Stored energy at removal 409.814 MJ/m². Net flux jumps from 0.002 to -3.998 W/m² without a temperature jump. The forcing is removed, not maintained forever; the long-time post-pulse target is zero anomaly. This is not a CO₂-emissions or real climate-sensitivity forecast.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Give the energy imbalance somewhere to go

An imbalance of 4 W/m² means four joules enter storage each second per square meter at the initial state. It does not mean temperature increases by four degrees each year. To connect energy with temperature, first specify how much energy the modeled reservoir stores for each degree of warming.

Imagine two containers with the same exposed area but different amounts of water. Under the same initial energy supply per area, the larger amount requires more energy for the same temperature change. This comparison motivates heat capacity; it is not a physical experiment performed by this interface.

The lab uses an effective water-equivalent depth H, from 10 to 200 m. Its areal heat capacity is C = 4.1 × 10⁶H J m⁻² K⁻¹. The word effective matters: this is a synthetic uniform reservoir, not a measured ocean layer or a model of ocean currents. NASA describes energy exchanges within the broader Earth system in its energy-budget explanation.

Calculate an initial rate with units

At H = 50 m, C = 205,000,000 J m⁻² K⁻¹. Temperature anomaly θ begins at zero, so the initial temperature-dependent radiative terms are zero. Net incoming flux N is then 4 W/m², and the initial warming rate is N/C.

Dividing gives about 1.9512 × 10⁻⁸ K/s. Multiplying by 31,557,600 seconds per model year gives about 0.61576 K/year. This is the instantaneous initial rate, not a promise that every subsequent year warms by that amount. As θ changes, the radiative response changes the net flux.

Make a paper ledger for depths 50 and 100 m. Double the heat capacity, then predict the initial rate before inspecting the curves. The 100 m case has half the initial rate under the same forcing. Keep “joules stored per kelvin” separate from “joules arriving per second.”

Define the temperature and storage anomalies

Temperature anomaly θ is measured relative to this model’s initial equilibrium, not the 1951–1980 reference of the recorded climate dataset. A difference of one kelvin has the same size as one degree Celsius, but no absolute surface temperature is assigned here.

Stored-energy anomaly is E = Cθ. At H = 50 m and θ = 1 K, E = 205 million J/m², or 205 MJ/m². The display uses megajoules per square meter so the large numbers remain readable. One megajoule is one million joules.

The energy equation is C dθ/dt = N. Read dθ/dt as the rate at which the temperature anomaly changes. Multiplying by heat capacity converts that temperature rate back into an energy-transfer rate per area. No calculus calculation is required to interpret the units or the sign.

Follow the changing net flux

The imposed forcing is 4 W/m² for the first 25 years and zero afterward. Baseline radiative damping contributes −3.2θ W/m². A separate feedback contributes fθ W/m². Thus N = F − 3.2θ + fθ, where F is the imposed forcing and f is the selected feedback coefficient.

At the default f = 1.2, the combined temperature response is −2θ. As θ increases, this response reduces the initial imbalance. The model computes a continuous response using an exact solution, not a succession of years each receiving the initial net flux.

Inspect the ledger at years 0, 5 and 10. Reconstruct N from its three terms, then use its sign to predict whether storage is increasing or decreasing. The ledger contains synthetic calculated states, not measured ocean heat-content observations.

Transfer to an unfamiliar reservoir

A paper reservoir has C = 100 million J m⁻² K⁻¹ and an initial net input of 2 W/m². Calculate its initial warming rate in K/year and its stored-energy anomaly at θ = 0.5 K. Use the model’s seconds-per-year convention.

Check the energy-storage transfer

The initial rate is 2/100,000,000 K/s, or 0.631152 K/year. Stored energy at 0.5 K is 50 million J/m² = 50 MJ/m². The initial rate need not persist when the net flux responds to temperature.

Apply

At unchanged forcing, doubling heat capacity makes the initial warming rate:

Public practice checks a specific claim. It does not establish independent mastery.

Distinguish flux, energy and temperature units, and explain why an initial rate does not remain constant throughout the experiment.

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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