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SCIENCE · INVESTIGATE AND EXPLAIN

Distinguish a pH ratio from a differential amount reserve

Equal buffer ratios need not provide equal resistance to an added amount.

Learning outcome: Hold the pH offset fixed while scaling total concentration, then scan pH to find the capacity maximum. Separate buffer-family and water terms, and reject large-addition claims from a local derivative.

Starting recap

Refresh proton equivalents, conjugate pairs, logarithmic dimensionless activity, analytical amount/volume, mass and charge balances, and bounded observational criteria.

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Try

At pH=pKa and total .100 M, the buffer-family differential capacity is ln(10)×.100/4≈.0575646 mol/(L pH), before adding the water contribution.

Open the experiment

Predict

Can two buffers have equal pH while one needs twice as much small added base for the same pH change?

Experiment

Hold the pH offset fixed while scaling total concentration, then scan pH to find the capacity maximum. Separate buffer-family and water terms, and reject large-addition claims from a local derivative.

Compare buffer ratio with differential capacity

Worked teaching model · synthetic values · Fictional monoprotic ideal buffer, pKa 5, Kw10⁻¹⁴, fixed volume and temperature. Differential strong-base capacity β=ln(10)[C Ka h/(Ka+h)²+h+Kw/h] in mol/(L pH). Local derivative, not a promise about a large finite addition or an unlimited buffer.

Reset keeps your prediction, captures and practice history.

buffer-family capacity (mol/(L pH))pH070.057564630
  • Buffer-family capacity: solid

Axes rescale. A concentration scan, imposed-pH distribution and titration curve have different horizontal meanings. Read each axis and preserve the difference between an imposed condition and an inferred equilibrium.

All calculated plot coordinates
Buffer-family capacity
pHbuffer-family capacity (mol/(L pH))
30.002257215
3.040.002470266
3.080.002702933
3.120.002956925
3.160.003234079
3.20.003536368
3.240.003865903
3.280.004224942
3.320.004615888
3.360.005041293
3.40.005503858
3.440.006006428
3.480.006551987
3.520.007143646
3.560.007784633
3.60.008478267
3.640.009227937
3.680.01003706
3.720.01090906
3.760.01184728
3.80.01285497
3.840.01393515
3.880.01509058
3.920.01632365
3.960.01763624
40.01902963
4.040.02050432
4.080.02205993
4.120.02369499
4.160.02540684
4.20.0271914
4.240.02904305
4.280.03095446
4.320.0329165
4.360.0349181
4.40.03694623
4.440.03898588
4.480.04102012
4.520.04303026
4.560.04499603
4.60.04689589
4.640.04870739
4.680.05040767
4.720.05197394
4.760.05338411
4.80.05461733
4.840.05565469
4.880.05647973
4.920.05707905
4.960.05744272
50.05756463
5.040.05744272
5.080.05707905
5.120.05647973
5.160.05565469
5.20.05461733
5.240.05338411
5.280.05197394
5.320.05040767
5.360.04870739
5.40.04689589
5.440.04499603
5.480.04303026
5.520.04102012
5.560.03898588
5.60.03694623
5.640.0349181
5.680.0329165
5.720.03095446
5.760.02904305
5.80.0271914
5.840.02540684
5.880.02369499
5.920.02205993
5.960.02050432
60.01902963
6.040.01763624
6.080.01632365
6.120.01509058
6.160.01393515
6.20.01285497
6.240.01184728
6.280.01090906
6.320.01003706
6.360.009227937
6.40.008478267
6.440.007784633
6.480.007143646
6.520.006551987
6.560.006006428
6.60.005503858
6.640.005041293
6.680.004615888
6.720.004224942
6.760.003865903
6.80.003536368
6.840.003234079
6.880.002956925
6.920.002702933
6.960.002470266
70.002257215
Calculated under the declared model
QuantityValueUnit
Selected pH5pH units
Base to acid equilibrium ratio1ratio
Buffer-family differential capacity0.05756463mol/(L pH)
Water differential contribution2.302815e-5mol/(L pH)
Total differential capacity0.05758766mol/(L pH)

The same conjugate ratio can have the same pH but a different amount reserve and differential capacity.

At fixed total concentration the buffer-family contribution peaks at h=Ka, or pH=pKa, with value ln(10)C/4. Scaling total concentration scales that contribution but not the ratio-based pH. This is a local fixed-volume derivative; use finite neutralization and a new equilibrium calculation for large additions. Water contributes separately.

These calculated packets are not performed chemical measurements. Keep feasible inventories, activity conventions, fitting observations and independent checks distinct.

The same conjugate ratio can have the same pH but a different amount reserve and differential capacity.

At fixed total concentration the buffer-family contribution peaks at h=Ka, or pH=pKa, with value ln(10)C/4. Scaling total concentration scales that contribution but not the ratio-based pH. This is a local fixed-volume derivative; use finite neutralization and a new equilibrium calculation for large additions. Water contributes separately.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Derive the local distinction

The ratio A−/HA fixes pH under an ideal monoprotic equilibrium relation. It does not fix how much material is available to accept or donate protons. At fixed volume, a small strong-base addition changes the acid-family partition and the water-ion inventory.

For total concentration C, the differential capacity is beta=ln(10)[C Ka h/(Ka+h)²+h+Kw/h], in mol per liter per pH unit. The first term belongs to the buffer family; the final two represent water. It is a local derivative under the stated fixed conditions, not a universal finite-addition formula.

Find the maximum and its domain

The family contribution peaks at h=Ka, where equal conjugate amounts give ln(10)C/4. At C=.100 M this is about.0575646 mol/(L pH). Doubling C doubles this contribution at the same pH ratio. Water contributes separately and can dominate outside the buffer’s useful range.

A target pH within roughly one unit of pKa corresponds to ratios from about.1 to 10, but no single ratio rule guarantees sufficient capacity for a specified large disturbance. That question requires an actual amount budget and new equilibrium solution.

Transfer and check

At pH=pKa with C=.0400 M, family beta≈.0230259 mol/(L pH). A sufficiently small .00100 mol/L base addition suggests a local change near.04343 pH units if the water contribution is negligible. Explain why applying that derivative to a .0300 mol/L addition would be unjustified without re-solving the finite composition.

Source and evidence boundary

Conceptual reference checked 30 October 2026: OpenStax Chemistry 2e. Prose, numerical packets and diagrams are original. All chemistry is fictional or supplied; no substance handling, mixing, titration apparatus or health interpretation is requested. The ideal concentration approximation, fixed temperature and inert-ion assumptions are explicit, not measured calibration. Retain your charge/mass balance, prediction, changed-case check and limits.

Apply

At fixed pH=pKa, doubling total buffer concentration makes its family capacity:

Public practice checks a specific claim. It does not establish independent mastery.

Why does a local differential capacity not replace a finite stoichiometric neutralization table?

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