Connect a measured mass to a particle amount
Compare two samples using mass, moles and explicitly named entities.
Learning outcome: Convert mass to amount using molar mass and distinguish equal masses from equal molecule numbers.
Starting recap
Scientific notation 6.02 × 10^23 means 6.02 multiplied by a power of ten. A ratio can convert units.
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Try
18 g water and 44 g carbon dioxide have different masses. Could they contain the same number of molecules?
Open the experimentPredict
Predict which sample has more molecules when each mass is 44 g. Explain what information you need besides mass.
Experiment
Capture (18,44), then (44,44), then (9,22). Compare equal amounts, equal masses and half-sized samples. Keep the entity labels.
Compare mass, amount and molecule number
Worked teaching model · synthetic values · Separate pure samples; rounded teaching molar masses H2O = 18 g/mol and CO2 = 44 g/mol. These are not exact physical constants. Avogadro constant is exact; computed counts inherit mass and molar-mass assumptions.
Reset keeps your prediction, captures and practice history.
Read left to right: each conversion uses the quantity and units from the preceding box. NA denotes the Avogadro constant; notation such as 6.022e+23 means 6.022 × 10^23 molecules.
| Row | Quantity | Value (mol) |
|---|---|---|
| 1 | Water amount (H2O molecules) | 1 |
| 2 | Carbon dioxide amount (CO2 molecules) | 1 |
1.0000 mol H2O; 1.0000 mol CO2.
Amount n = mass m / molar mass M. Water molecules ≈ 6.0221e+23; CO2 molecules ≈ 6.0221e+23. Entity counts refer to molecules, not total atoms. Display rounding is not additional measurement precision.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Use unit cancellation to explain the comparison. Distinguish one mole of water molecules from one mole of hydrogen atoms.
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