Test a molecular explanation against independent evidence
Combine controlled model comparisons with an explicitly synthetic functional-evidence packet.
Learning outcome: Distinguish chemical and functional claims, retain uncertainty and propose a discriminating follow-up.
Starting recap
A structural representation, chemical inventory and functional assay answer different questions. Shared inputs make repeated outputs dependent evidence.
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Try
A fictional treated sample loses binding while its backbone assay detects no cleavage; a separate hydrolyzed sample contains fragments.
Open the experimentPredict
Predict which explanation each measurement can support and what result would challenge it.
Experiment
Capture all three-cut geometry comparisons and verify their identical chemistry. Then analyze the separate paper packet in Understand: compare matched samples, record the assay limit, and propose a blank and a follow-up.
Separate peptide backbone chemistry from its depiction
Worked teaching model · synthetic values · Original eight-residue teaching chain, not an identified natural protein. Compact and extended views are supplied geometry only, not equilibrium folds or evidence of activity. Cuts are prescribed complete hydrolysis events, not a rate or enzyme-specificity model. Neutral molecular formulas provide atom bookkeeping; actual protonation depends on conditions. No cysteine/disulfide bonds, side-chain reactions, energetics or biological function are calculated. Net free-amino-acid condensation is not the mechanism of ribosomal synthesis: activated aminoacyl-tRNA transfer is involved.
Reset keeps your prediction, captures and practice history.
Change a drawing or change a covalent bond
Predict first: does changing the compact drawing to the extended drawing consume water or create new fragments? Then keep the drawing fixed and compare a hydrolysis pattern. This is an original eight-residue teaching chain, not an identified natural protein.
Compact reference schematic. Solid lines represent the remaining peptide-backbone connections; each numbered node is a whole amino-acid residue, not an atom. An × marks a prescribed broken connection, with no line bridging it. Reading residue numbers from 1 to 8 follows the original N-to-C sequence.
Compact reference schematic. Residues in N-to-C sequence: Gly, Ala, Ser, Val, Gly, Ala, Ser, Val. All seven peptide bonds are intact. There are 1 fragments. Geometry is a supplied illustration, not a predicted fold. Cut fragments retain the selected drawing positions only; their actual shapes and separation are not calculated.
7 peptide bonds remain; 1 fragment; 0 water molecules consumed per original chain. The covalent hydrolysis operation adds one H and one OH across each cleaved bond, creating an additional pair of termini. Changing depiction alone does none of this.
| Fragment | Original residues / N to C | Length | Peptide bonds | Neutral formula |
|---|---|---|---|---|
| 1 | 1–8: Gly–Ala–Ser–Val–Gly–Ala–Ser–Val | 8 | 7 | C26H46N8O11 |
Account for the water as part of the reacting system
C26H46N8O11 + 0 H₂O → aggregate products C26H46N8O11. “Aggregate” means the summed composition of all fragments, not one new molecule. The water is consumed, not created, by these prescribed hydrolysis events.
| Element | Intact peptide | Consumed water contributes | Total before | All fragments after |
|---|---|---|---|---|
| C | 26 | 0 | 26 | 26 |
| H | 46 | 0 | 46 | 46 |
| N | 8 | 0 | 8 | 8 |
| O | 11 | 0 | 11 | 11 |
The free amino acids sum to C26H60N8O18. Subtracting seven H₂O gives the intact peptide's composition. That subtraction is bookkeeping, not a reaction mechanism for ribosomal synthesis: cells transfer an activated tRNA-bound chain during elongation. Actual protonation depends on solution conditions; this neutral-form ledger does not model buffer exchange.
What the structure evidence can establish
A peptide bond is covalent. Hydrogen bonds and other interactions can help organize a chain in water without cutting its peptide backbone. Water's polar O–H bonds are covalent within each water molecule; a hydrogen bond between suitable groups is a different interaction. Unfolding and hydrolysis are therefore different hypotheses, even when either could accompany a change in activity.
The conformation control supplies a different drawing; it does not simulate a treatment, demonstrate unfolding or predict activity. No hydrogen-bond count, affinity, rate or energy is inferred. The sequence contains no cysteine, so this model contains no disulfide links.
Check the prediction and transfer it
Changing only the depiction preserves every fragment, formula and water count. Hydrolyzing after residue 4 gives two four-residue fragments, each C13H24N4O6, and consumes one H₂O. A sample with unchanged composition but lower activity does not by itself prove unfolding: an inhibitor, a changed amount of active material or another cause could explain it. Propose a fragment/sequence measurement and a controlled activity comparison before choosing an explanation. This hypothetical sample is not an observed result produced by the drawing.
Read the model boundaries
Original eight-residue teaching chain, not an identified natural protein. Compact and extended views are supplied geometry only, not equilibrium folds or evidence of activity. Cuts are prescribed complete hydrolysis events, not a rate or enzyme-specificity model. Neutral molecular formulas provide atom bookkeeping; actual protonation depends on conditions. No cysteine/disulfide bonds, side-chain reactions, energetics or biological function are calculated. Net free-amino-acid condensation is not the mechanism of ribosomal synthesis: activated aminoacyl-tRNA transfer is involved.
1 fragment; 7 peptide bonds remain; 0 water molecules consumed per starting chain.
Aggregate neutral product formula C26H46N8O11. Depiction changes neither this formula nor the selected cut pattern. No activity, exact folding or rate is predicted.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Write a bounded claim, one alternative cause and the measurement needed to distinguish it. Explain why no detected cleavage is not proof of zero cleavage.
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
Skipping retains experiments and awards no mastery.
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