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SCIENCE · INVESTIGATE AND EXPLAIN

Locate a fault using node and current constraints

Explain complementary voltage and current readings with explicit topology and polarity.

Learning outcome: Use junction potential and loop current to distinguish the supplied fault cases without equating zero voltage with an open circuit.

Starting recap

Junction voltage means junction minus return potential. An intact ideal resistor at zero current has zero voltage drop.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

Junction voltage 0 V occurs for both open R1 and bypassed R2, but their currents are 0 and 60 mA.

Open the experiment

Predict

Predict why a 0 V junction does not by itself distinguish a disconnected upstream path from a downstream bypass.

Experiment

Use an available case to predict and record junction voltage followed by current. If its budget is already used, analyze the retained pair or work on paper instead. Explain each surviving mechanism from the schematic.

Diagnose with two distinct readings

Worked teaching model · synthetic values · Original finite ideal-circuit cases. Selecting a probe does not take a reading. A separate notebook preserves predictions and at most two distinct readings per case. Public source and worked answers are available; this is guided practice, not secret assessment. No real circuit is energized.

Reset keeps your prediction, captures and practice history.

Choose evidence before naming a fault

Case A uses one of five supplied ideal hypotheses. All cases and source answers are public. Familiarity, answer reveal and repeated readings are retained; they do not create independent assessment evidence. This notebook is shared across the four diagnosis lessons.

V+−R1 = 100 ΩR2 = 200 ΩJReturn: 0 V referenceNominal source: 6 V
Nominal reference topology, identical for every unrevealed case. Terminal voltage: positive terminal minus return. Junction voltage: J minus return, across R2. Positive loop current flows from the positive terminal through R1 toward R2. Ideal voltage/current meters do not load this model.

Possible explanations: healthy circuit, open R1, open R2, bypassed R2, or weak ideal source. The open cases leave J connected to a source terminal through a resistor. This finite set excludes simultaneous faults, contact resistance and meter loading.

Notebook changes wait while science storage is loading.

Retain your initial plan for case A

Reading allowance: 0/2 distinct probes

Proposed next probe: Source terminal voltage. Choosing it above reveals no value. Repeating a retained probe replays the same reading without spending another slot. Changing cases or resetting controls keeps all case histories.

Case A: ordered, retained predictions and ideal readings
Order / probePrediction before readingValueAnswer already exposed?

Compatible supplied hypotheses: Healthy series pair; Open R1; Open R2; Bypassed R2; Weak ideal source

Compatibility means agreement with the retained readings, not a probability or proof that all real alternatives have been eliminated. Before any reading all five remain. Terminal voltage plus current can leave both open-circuit hypotheses; keep the ambiguity and justify a next test on paper.

This conclusion remains editable; your prior and reading predictions remain unchanged. Generic lesson captures preserve only selectors, not additional readings.

Case A: choose and justify a reading in the notebook.

Generic captures retain selections only. They do not take readings, spend the measurement allowance or establish a diagnosis.

Captures preserve case and proposed-probe selectors only. They reveal no reading and do not replace the shared diagnosis notebook's retained predictions and two-reading limit.

Understand

Locate a mechanism, not a colored component

A display shows junction voltage 0 V. That does not automatically mean the circuit is open or that the source is off. Voltage compares two points: here it is junction potential minus return potential. Two points can share a potential while current flows elsewhere in the circuit. Trace the connections and ask which other reading would distinguish the candidate mechanisms.

The nominal path is source positive → R1 → junction → R2 → return, with R1 = 100 Ω and R2 = 200 Ω. The source is ideally 6 V except in the explicitly supplied weak-source case. Positive loop current follows that path. The model’s probes preserve these definitions; a negative value introduced by reversing a paper voltmeter’s leads would require a changed polarity statement, not a new fault name.

Explain a zero junction two ways

If R1 is open, no complete source-to-return path exists. Current is zero. The junction connects to return through intact R2, and the drop across that resistor is I × R2 = 0 × 200 = 0 V. Thus the junction sits at return potential. The full source difference appears across the upstream break rather than across R2.

If R2 is bypassed, an ideal wire instead holds the junction at return potential. R1 still has a complete path to the source. Current is 6/100 = 0.060 A = 60 mA. The same zero junction voltage therefore accompanies two very different currents. A current reading after the zero junction result distinguishes those two supplied explanations.

This does not mean zero resistance can be inserted into every existing solver. The bypass changes topology; its equation is derived for that path. These are virtual cases, and the illustration is not a direction to make an actual energized bypass.

Explain an open downstream component

With R2 open, the loop current is again zero. But the junction remains connected to source positive through intact R1. Its zero-current drop is 0 V, putting the junction at 6 V relative to return. A voltmeter can therefore indicate nonzero voltage across a break while no loop current flows. The ideal voltmeter draws no current, so it does not restore the loop.

Together, junction and current give these mechanism pairs: healthy 4 V, 20 mA; open R1 0 V, 0 mA; open R2 6 V, 0 mA; bypassed R2 0 V, 60 mA; weak ideal source 2 V, 10 mA. These predictions are unique within the supplied set. They are not a universal dictionary of real circuit faults.

Check a healthy result through two relationships

For the healthy circuit, current 0.020 A predicts R1’s drop as 2 V and R2’s as 4 V. Their sum is 6 V. The junction-relative-to-return reading independently constrains the lower segment’s voltage, while the current constrains the whole series path. “Independent” here refers to complementary physical constraints, not a proven statistical independence of instrument errors.

You can also check power on paper: source power is 6 × 0.020 = 0.120 W. R1 dissipates 0.020² × 100 = 0.040 W and R2 dissipates 0.080 W. Their sum closes the ideal electrical energy-rate account. This calculation does not predict resistor temperature or practical component ratings. OpenStax’s resistor treatment supplies the underlying current, voltage and power relationships; the diagnostic comparisons here are original.

Keep the evidence sequence visible

For an available case, predict junction voltage first, record it in the dedicated notebook, then predict current from the surviving mechanisms before requesting it. Retain both original predictions. If that case’s two slots were already used differently, analyze its saved pair or perform this sequence on paper; do not claim a new unexposed run. Case history and reveal exposure persist across navigation and reload.

Transfer: reverse a stated polarity

A hypothetical healthy case gives junction-minus-return = +4 V. On paper, reverse the voltmeter leads while leaving the circuit and current reference unchanged. Predict the new voltage and explain whether the current must reverse.

Check the polarity transfer

The voltmeter now reports return-minus-junction = −4 V. The physical circuit is unchanged, so the positive conventional loop current remains 20 mA under the original reference. A sign change caused by the measurement definition is not evidence of a reversed source or a new fault. Reversed leads are a paper extension, not an extra widget control.

Return to circuit power for the energy-rate check, or continue to diagnosis limits before generalizing from a successful finite-case match.

Apply

A case has junction voltage 0 V and current 60 mA. Which supplied mechanism is compatible?

Public practice checks a specific claim. It does not establish independent mastery.

Show the voltage and current constraints for the selected case and distinguish independent physical constraints from statistically independent measurements.

Continue

Completion requires a saved prediction, at least one capture and a reflection. This lesson also requires a case with two retained readings and a written diagnosis in the shared circuit notebook. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

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