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SCIENCE · INVESTIGATE AND EXPLAIN

Close both component orbits around a common center

Both members of a binary respond to the same mutual gravitational force, but their accelerations differ inversely with mass. Neither body must remain fixed. In the center-of-mass frame their position vectors are opposite and obey M₁r₁=M₂r₂. The more massive component follows the smaller orbit, while both complete a cycle in the same period.

Learning outcome: Vary secondary mass fraction at fixed relative axis, then vary axis at fixed fraction. Close the radius sum, mass-weighted position and opposite momenta, and identify an observation that distinguishes barycenter from photocenter.

Starting recap

Retain relative versus barycentric geometry, time versus angle, fitted versus instantaneous velocity and complete energy/angular-momentum boundaries.

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Try

At a=4 AU and secondary fraction 0.25, masses are 3 and 1 solar masses, radii 1 and 3 AU, and period 4 years. Speeds are π/2 and 3π/2 AU/year. Position balance is −3×1+1×3=0; opposite momentum magnitudes are each 3π/2.

Open the experiment

Predict

Does the heavier star follow the larger or smaller path around the common center?

Experiment

Vary secondary mass fraction at fixed relative axis, then vary axis at fixed fraction. Close the radius sum, mass-weighted position and opposite momenta, and identify an observation that distinguishes barycenter from photocenter.

Close binary positions and momenta around the common center

Worked teaching model · synthetic values · Original circular binary total mass 4 solar masses, conventional P²=a³/M. Primary axis=a f, secondary axis=a(1−f); both have the same period. Displayed velocities are opposite tangential directions at the shown phase; no mass-luminosity assumption.

Reset keeps your prediction, captures and practice history.

The heavier component follows the smaller barycentric orbit while both share one period.

Their relative separation is the sum of the two barycentric radii. Opposite momenta cancel in the center-of-mass frame; equal gravitational force does not imply equal acceleration, speed or radius. Brightness is not used to assign mass.

Primary mass 3; secondary mass 1Both circles share the barycenter; relative separation is the radius sumOriginal diagram, no measured size, luminosity or sky projection
Original conditional quantities and explicit units
QuantityValueUnit
Primary mass3solar masses
Secondary mass1solar masses
Primary barycentric radius1AU
Secondary barycentric radius3AU
Common period4years
Primary tangential speed1.570796AU/year
Secondary tangential speed4.712389AU/year
Signed center-of-mass numerator0solar mass AU
Signed momentum sum0solar mass AU/year

These original models are not measured orbit records or operational mission instructions. Retain the frame, assumptions and missing evidence before interpreting a real system.

The heavier component follows the smaller barycentric orbit while both share one period.

Their relative separation is the sum of the two barycentric radii. Opposite momenta cancel in the center-of-mass frame; equal gravitational force does not imply equal acceleration, speed or radius. Brightness is not used to assign mass.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

1. Define the orbital evidence

Both members of a binary respond to the same mutual gravitational force, but their accelerations differ inversely with mass. Neither body must remain fixed. In the center-of-mass frame their position vectors are opposite and obey M₁r₁=M₂r₂. The more massive component follows the smaller orbit, while both complete a cycle in the same period.

2. Connect geometry, force and conservation

The original circular binary has total mass 4 solar masses and relative separation a AU. If the secondary mass fraction is f, then M₂=4f and M₁=4(1−f). The primary radius is af and the secondary radius a(1−f), adding to a. The shared period is √(a³/4) years. The fraction labels refer to mass, not flux or a spectral brightness estimate.

Each speed is 2π times its own radius divided by the common period. At the displayed phase the tangential velocities are opposite, so signed total momentum cancels. This is a useful independent check on both mass and speed assignments. Equal force does not mean equal speed or equal radius unless the component masses are equal.

The original diagram shows circular barycentric orbits in their orbital plane. Real visual binaries can be eccentric and projected, and measured image positions can refer to a light-weighted photocenter rather than the mass center. A source-labeled bright spot is not automatically the center of mass. Those additional observations and assumptions must be retained before real mass inference.

3. Work the original case

At a=4 AU and secondary fraction 0.25, masses are 3 and 1 solar masses, radii 1 and 3 AU, and period 4 years. Speeds are π/2 and 3π/2 AU/year. Position balance is −3×1+1×3=0; opposite momentum magnitudes are each 3π/2.

4. Predict and investigate

Does the heavier star follow the larger or smaller path around the common center?

Vary secondary mass fraction at fixed relative axis, then vary axis at fixed fraction. Close the radius sum, mass-weighted position and opposite momenta, and identify an observation that distinguishes barycenter from photocenter.

Apply the evidence to a changed case

At relative a=2 AU and equal masses, find component radii, common period and speeds. Compare the relative orbital axis with either component radius.

Retain the evidence frame, calculations and assumptions before opening public feedback.

Compare a worked response

Each mass is 2 solar masses and each radius 1 AU. Period is √2 years and each speed is √2π AU/year. The relative axis is 2 AU, twice either barycentric radius; equal brightness was not assumed.

Source and boundaries

Primary mechanism reference. Checked 30 October 2026. Original prose, numerical cases and diagrams; source context is not a claim that these fictional records were observed. No actual mission operation or instrument aiming is requested.

Apply

For total mass 4 and secondary fraction 0.25 at relative axis 4 AU, which assignment closes the center of mass?

Public practice checks a specific claim. It does not establish independent mastery.

At relative a=2 AU and equal masses, find component radii, common period and speeds. Compare the relative orbital axis with either component radius.

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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