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Lesson 14 of 18

Analyze differences before applying t

Preserve matching and define the sign of change.

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A team measures the same people’s completion times before and after training. Two columns of numbers do not create two independent samples. Each participant supplies a matched comparison. Define d as after minus before so that a negative value means a reduction in completion time.

Predict

Predict which spread should enter the standard error: the SD of all measurements pooled together, or the SD of the within-person differences. Stable differences between people can be large even when their changes are similar. Pairing aims to retain that matching information rather than discarding it.

Experiment

Use an original synthetic difference sample d=−1,1,2,3,5 minutes. Its mean is 10/5=2. Deviations from 2 are −3,−1,0,1,3, whose squared sum is 20. Sample variance is 20/4=5 and SD is √5. Estimated SE is √5/√5=1.

For a 95% interval use supplied t*=2.776 at df=4. The interval is 2±2.776=[−0.776,4.776]. It describes mean after-minus-before change under a suitable model, not the distribution of individual changes. This tiny sample needs strong attention to the difference distribution and design.

Understand

A paired analysis first reduces each complete pair to one difference using a consistent orientation. The target μd is the population or study-setting mean of those differences. The usual interval is d̄±t* sd/√n, and the test statistic for a null μd0 is (d̄−μd0)/(sd/√n), with n equal to the number of independent pairs and df=n−1.

For small samples, assess the shape of the differences, not merely the separate before and after columns. The paired t model treats differences as independent observations from a sufficiently appropriate distribution. Measurements within a pair may be strongly related; that is the structure being preserved. Different pairs still need independence or a method accounting for their dependence.

Paired data can come from repeated measurements on one unit or from carefully matched different units. In a crossover experiment, treatment order and carryover matter. Randomize order where appropriate, use comparable tasks and allow suitable washout or practice controls. Subtracting two numbers does not automatically remove time trends or learning effects.

A before-and-after mean change alone does not identify a causal treatment effect. Maturation, concurrent events and regression to the mean can contribute. Randomized comparison designs support stronger causal reasoning. State precisely whether the inference concerns change or an experimentally identified difference in changes.

Missing members of pairs require care. A complete-pairs analysis changes the included set; if dropout relates to outcome or adverse experiences, the remaining differences may be biased. Do not fill missing values with zeros, which would invent no change. Document missingness and use a justified analysis or sensitivity assessment.

Pairing can improve precision when within-pair association is informative, but it is not guaranteed to do so in every dataset. The benefit is a design question as well as an arithmetic one. Always report the pairing rule, sign convention, number of complete pairs and sample SD of differences.

Apply

Create a two-row example where people have very different baseline values but identical changes, and explain what pooling raw measurements hides. Then reverse your difference definition and verify how the mean, t sign and interval endpoints change while the substantive interpretation stays consistent.

Continue

Next compare independent quantitative groups. When there is no pairing and population variances may differ, use a separate-variance method such as Welch inference.

Apply · explain · revise

Practice and reasoning

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After-minus-before differences are 1,2,3,4,5. Find their sample mean.

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For those five differences, sample variance is 5/2. Find the squared standard error of their mean.

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Twelve participants are measured before and after. For a paired t analysis, df is:

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The normality/shape check in a small paired t analysis primarily concerns:

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Sixteen independent pairs have mean after-minus-before difference −2 and SD of differences 4. Give a 95% interval using t*=2.131 and interpret the sign.

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A single group improves after training, with a narrow paired interval. Why does pairing alone not establish a training effect?

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