Cut a cylinder along one vertical generator and unroll it. In coordinates u measuring circumference and v measuring height, its first form is du²+dv². Every curve contained in a suitable patch has the same length before and after this local unrolling.
The full wrapping map from the entire plane is different. Points separated by 2πR in the u direction have the same image. A map can preserve tangent lengths locally while failing to preserve global point-to-point distances or injectivity.
Predict
Predict whether a local isometry must preserve the shape operator. The plane and cylinder have different principal curvatures, so it cannot. Gaussian curvature is preserved by the intrinsic Gauss theorem developed later.
Predict whether an angle-preserving map is necessarily an isometry. Uniform scaling preserves angles but multiplies lengths. A variable positive conformal scale preserves pointwise angles while changing lengths along paths.
Experiment
Separate three preservation claims.
Map or metric change
Angles
Local lengths
Global injectivity
Plane to a short cylinder patch
Preserved
Preserved
Yes on that patch
Full plane wrapping onto cylinder
Preserved locally
Preserved locally
No
Metric multiplied by e^(2φ)
Preserved at each point
Generally changed
Not the relevant question
Choose two plane points a full circumference apart and verify their images coincide. This is an exact obstruction to global isometry even though the pullback metric calculation is correct everywhere.
Understand
A local diffeomorphism F between Riemannian surfaces is a local isometry when ⟨dF(v),dF(w)⟩ at the image equals ⟨v,w⟩ at the source for every tangent pair. By the chain rule it preserves curve speeds and hence lengths for curves in its domain. The cylinder wrapping map has this property because its coordinate derivatives are orthonormal.
For a conformal metric g=e^(2φ)(dx²+dy²), the angle numerator and the product of vector norms both acquire e^(2φ). Their quotient is unchanged, proving angle preservation. A curve’s speed instead acquires e^φ, whose integral generally changes. Conformality is therefore weaker than isometry.
Intrinsic distance is the infimum of lengths over all connecting surface paths. A local isometry preserves sufficiently local distance behavior, but a global shortcut or identification can change the infimum over all paths. This explains why a pullback identity alone does not prove a global metric-space isometry.
Apply
Repair “Equal Gaussian curvature proves global isometry.” Even once K is known intrinsic, matching one scalar function does not generally determine a global metric. A plane and a cylinder both have K=0 but differ globally. Local constant-curvature classification requires a separate theorem, and variable curvature data can be subtler still.
For optional depth, a Riemannian metric can be defined abstractly by smooth positive-definite bilinear forms without a preferred embedding. Coordinate transformation rules keep the definition consistent across charts. Connections, geodesics and intrinsic curvature can then be constructed from the metric alone; principal curvatures require an embedding and normal.
The immediate goal is to derive that metric connection rather than rely on the visual intuition of unrolling.
Continue
When claiming two surfaces are equivalent, specify local or global, angle or length, and whether an embedding must be preserved. Continue to Christoffel symbols and the connection to differentiate tangent fields intrinsically.
Apply · explain · revise
Practice and reasoning
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For g=4(dx²+dy²), find the squared metric norm of vector (1,2).
Integers, fractions and finite decimals are accepted. Expressions such as sqrt(2) are not parsed by this checker.
A local isometry necessarily preserves
Prove X(u,v)=(R cos(u/R),R sin(u/R),v) is a local isometry from the plane to a cylinder.
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Give two plane points showing that the full cylinder wrapping map is not a global metric isometry.
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Show g=e^(2φ)(dx²+dy²) preserves Euclidean angles at a point but generally not curve lengths.
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Why does cylinder bending preserve K but not necessarily principal curvatures? State the role of Theorema Egregium.
Structure your argument and preserve revisions
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Reflect and continue
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